解决MVC 时间序列化的方法

1.全局处理

处理代码

  publict static void SetSerializationJsonFormat(HttpConfiguration config)
         {
             // Web API configuration and services
             var json = config.Formatters.JsonFormatter;
             ////(时间格式只支持2种)json.SerializerSettings.DateFormatHandling = Newtonsoft.Json.DateFormatHandling.MicrosoftDateFormat;
             ////时间格式("自定义格式")
             json.SerializerSettings.Converters.Add(new IsoDateTimeConverter { DateTimeFormat = "yyyy-MM-dd HH:mm:ss" });
             ////移除json序列化器
             ////config.Formatters.Remove(config.Formatters.JsonFormatter);
         }

在Application_Start调用SetSerializationJsonFormat(GlobalConfiguration.Configuration)全局设置

2.重写ActionResult

     public class JsonResult : ActionResult
     {
         public JsonResult()
         {
             this.ContentEncoding = Encoding.UTF8;
             this.ContentType = "application/json";
         }

         public override void ExecuteResult(ControllerContext context)
         {
             if (context == null)
             {
                 throw new ArgumentNullException("context");
             }

             HttpResponseBase response = context.HttpContext.Response;
             if (!string.IsNullOrEmpty(this.ContentType))
             {
                 response.ContentType = this.ContentType;
             }
             if (this.ContentEncoding != null)
             {
                 response.ContentEncoding = this.ContentEncoding;
             }
             if (this.Data != null)
             {
                 response.Write(NewtonsoftSerialize(this.Data));
                 response.End();
             }
         }

         public Encoding ContentEncoding { get; set; }

         public string ContentType { get; set; }

         public object Data { get; set; }

         private static string NewtonsoftSerialize(object value)
         {
             try
             {
                 IsoDateTimeConverter timeFormat = new IsoDateTimeConverter { DateTimeFormat = "yyyy-MM-dd HH:mm:ss" };
                 return JsonConvert.SerializeObject(value, timeFormat);
             }
             catch
             {
                 return string.Empty;
             }
         }
     }