A. Neverending competitions
time limit per test

2 seconds

memory limit per test

512 megabytes

input

standard input

output

standard output

There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.

Jinotega's best friends, team Base have found a list of their itinerary receipts with information about departure and arrival airports. Now they wonder, where is Jinotega now: at home or at some competition far away? They know that:

  • this list contains all Jinotega's flights in this year (in arbitrary order),
  • Jinotega has only flown from his hometown to a snooker contest and back,
  • after each competition Jinotega flies back home (though they may attend a competition in one place several times),
  • and finally, at the beginning of the year Jinotega was at home.

Please help them to determine Jinotega's location!

Input

In the first line of input there is a single integer n: the number of Jinotega's flights (1 ≤ n ≤ 100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next n lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX" is the name of departure airport "YYY" is the name of arrival airport. Exactly one of these airports is Jinotega's home airport.

It is guaranteed that flights information is consistent with the knowledge of Jinotega's friends, which is described in the main part of the statement.

Output

If Jinotega is now at home, print "home" (without quotes), otherwise print "contest".

Examples
Input
4
SVO
SVO->CDG
LHR->SVO
SVO->LHR
CDG->SVO
Output
home
Input
3
SVO
SVO->HKT
HKT->SVO
SVO->RAP
Output
contest
Note

In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list.

 #include <iostream>
#include <cstdio>
#include <cstring> using namespace std; int main()
{
int n, cnt1, cnt2;
string src, line;
while(cin>>n)
{
cnt1 = ;
cnt2 = ;
cin >> src;
for(int i = ; i < n; i++)
{
cin>>line;
if(src[] == line[] && src[] == line[] && src[] == line[]) cnt1++;
if(src[] == line[] && src[] == line[] && src[] == line[]) cnt2++;
}
if(cnt1==cnt2) cout<<"home"<<endl;
else cout<<"contest"<<endl;
}
return ;
}

765A Neverending competitions的更多相关文章

  1. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) A. Neverending competitions 水题

    A. Neverending competitions 题目连接: http://codeforces.com/contest/765/problem/A Description There are ...

  2. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) A - Neverending competitions

    地址:http://codeforces.com/contest/765/problem/A 题目: A. Neverending competitions time limit per test 2 ...

  3. 【codeforces 765A】Neverending competitions

    [题目链接]:http://codeforces.com/contest/765/problem/A [题意] 给你一个人的n个行程 行程都是从家到某个地方或从某个地方到家; 且是无序的,且如果到了非 ...

  4. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined)

    运气好,分到的房里我最先开始Hack C题,Hack了12个,听说F题沙雕莫队但我不会,最后剩不到15分钟想出E题做法打了一波结果挂了,最后虽然上分了但总有点不甘心. 最后A掉ABCD Hack+12 ...

  5. CodeForces765A

    A. Neverending competitions time limit per test:2 seconds memory limit per test:512 megabytes input: ...

  6. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) A B C D 水 模拟 构造

    A. Neverending competitions time limit per test 2 seconds memory limit per test 512 megabytes input ...

  7. Codeforces Round #397 题解

    Problem A. Neverending competitions 题目大意 一个团队有多个比赛,每次去比赛都会先订机票去比赛地点,然后再订机票返回.给出\(n\)个含有起止地点的购票记录(不按时 ...

  8. Improving your submission -- Kaggle Competitions

    1: Improving Our Features In the last mission, we made our first submission to Titanic: Machine Lear ...

  9. Getting started with Kaggle -- Kaggle Competitions

    1: The Competition We'll be learning how to generate a submission for a Kaggle competition. Kaggle i ...

随机推荐

  1. JavaScript的灵活应用

    1.查找数组的最大值和最小值 (1) Math.max.qpply(null,array); Math.min.qpply(null,array); (2) eval("Math.max(& ...

  2. UVA548

    题意: 根据二叉树中序和后序建立二叉树,从根结点开始计算和到叶子结点,输出总和最小的叶子结点,如果有俩个和一样大,输出叶子结点最小的 AC:80ms #include<stdio.h> # ...

  3. 汇编环境配置及 Hello World。DOSBox,debug.exe,VisualStudio

    ▶ DOSBOX 相关 ● 下载 DOSBox(http://www.dosbox.com/download.php?main=1),安装到文件夹 DOSBox . ● 下载 debug.exe(Wi ...

  4. leetcode412

    public class Solution { public IList<string> FizzBuzz(int n) { var list = new List<string&g ...

  5. 浮动float 摆放位置

    <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...

  6. Linux&Unix命令

    Linux下: 系统操作 文件操作 防火墙 权限管理 压缩和解压 安装应用 用户管理 端口 PID 应用 start & shutdown 远程操作 异常 注意点: linux系统下内容大多用 ...

  7. c++ cout cin, 命名空间

    cout<<a<<endl; cout<<a; 返回值其实就是一个输出流,(cout就是输出流) 上述语句等价于(cout<<a)<<end ...

  8. unity 加载读取外部XML

    cfg.xml <rootNode> <category name="网站"> <item name="mainPage"> ...

  9. redis-trib.rb报错:/usr/lib/ruby/1.9.1/rubygems/custom_require.rb:36:in `require': cannot load such file -- redis (LoadError)

    报错如下: /usr/lib/ruby/1.9.1/rubygems/custom_require.rb:36:in `require': cannot load such file -- redis ...

  10. Implementing On Item Click / Double Click for TListView

    ListView.On Item Click & ListView.On Item Double Click To be able to locate the clicked (if ther ...