postgreSQL 应用case when的例子

select
name,
md5(indvl_id_nbr) as indvl_id_nbr,
case when char_length(indvl_id_nbr)=18 or char_length(indvl_id_nbr)=15 then substring(indvl_id_nbr from 1 for 6)
end as id_prefix,
case when char_length(indvl_id_nbr)=18 then substring(indvl_id_nbr from 7 for 8)
when char_length(indvl_id_nbr)=15 then '19' || substring(indvl_id_nbr from 7 for 6)
else null end as id_brth_dt
from myschema.table_test;
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作者：波特王子
来源：CSDN
原文：https://blog.csdn.net/sptoor/article/details/18309161
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