Sicily 1388. Quicksum

http://soj.me/1388

又一道字符串的水题....

#include <iostream>
#include <cstring>

using namespace std;

int main()
{
	char ch[260];
	while(cin.getline(ch,260))
	{
		if(ch[0] == '#') break;
		int ans = 0;
		int n = strlen(ch);
		for(int i=0;i < n;++i)
		{
			if(ch[i] >= 'A' && ch[i] <= 'Z')
				ans += (ch[i] - 'A' + 1)*(i + 1);
		}
		cout<<ans<<endl;
	}
	return 0;
}