Java 7.35 游戏：猜字游戏（C++&Java）

Ps：

有人可能好奇我为什么大费周章的去写主函数，而不直接把所有操作放在类中，Why？类就好比骨干（存放核心的数据和功能），最好提供接口， 避免了类中的输入输出，当然，这也不是绝对的。

C++：

#include<iostream>
#include<string>
#include<ctime>
using namespace std;
class GuessNumber {
public:
	void Get();
	int Guess(char);
	string get_g_word() {
		return g_word;
	}
	string get_word() {
		return word;
	}
	int get_miss() {
		return miss;
	}
private:
	int miss = 0;
	string words[7] = { "write","that","important","transform","judge","index","run" };
	string word;
	string g_word;
};
void GuessNumber::Get() {
	srand((unsigned int)time(0));          //随机数
	word = words[rand() % 7 ];       //伪随机数？——跟运行时间有关
	g_word=string(word.length(), '*');
}
int GuessNumber::Guess(char ch) {
	if (word.find(ch) == string::npos) {      //字母没有出现在单词中
		miss++;
		return 2;
	}
	if (g_word.find(ch) != string::npos) {    //已猜过（出现在g_word中）
		miss++;
		return 1;
	}
	for (int i = 0; i < word.length(); i++)    //猜中，修改g_word
		if (word[i] == ch)
			g_word[i] = ch;
	return  0;
}
int main() {
	char ch;
	string str;
	GuessNumber My;
	int key;
	while (1) {
		My.Get();
		while (My.get_g_word() != My.get_word()) {
			cout << "(Guess) Enter a letter in word " << My.get_g_word() << " > ";
			cin >> ch;
			key = My.Guess(ch);
			if (key == 2)
				cout << "     " << ch << " is not in the word" << endl;
			else if (key == 1)
				cout << "     " << ch << " is already in the word" << endl;
		}
		cout << "The word is " << My.get_word() << ". You missed " << My.get_miss() << " time " << endl;
		cout << "Do you want to guess another word? Enter y or n >";
		cin >> str;
		if (str == "n")
			break;
		system("cls");  //清屏
	}

	return 0;
}

Java：

请自己写。