https://leetcode.com/problems/single-number/

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

class Solution {
public:
int singleNumber(vector<int>& nums) {
if(nums.size() == ) return nums[]; vector<int> bitNums(, ); int res = ;
for(int i=;i<bitNums.size();++i) {
for(int j=;j<nums.size();++j) {
bitNums[i] += (nums[j] >> i) & ;
}
res |= (bitNums[i] % ) << i;
} return res;
}
};

https://leetcode.com/problems/single-number-ii/

Given an array of integers, every element appears three times except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

class Solution {
public:
int singleNumber(vector<int>& nums) {
if(nums.size() == ) return nums[]; vector<int> bitNums(, ); int res = ;
for(int i=;i<;++i) {
for(int j=;j<nums.size();++j) {
bitNums[i] += (nums[j] >> i) & ;
cout << ((nums[j] >> i) & ) << " ";
}
cout<<endl;
} for(int i=;i<bitNums.size();++i) {
res += (bitNums[i] % ) << i;
}
return res;
}
};

leetcode@ [136/137] Single Number & Single Number II的更多相关文章

  1. [LeetCode#136, 137]Single Number, Single Number 2

    The question: Single Number Given an array of integers, every element appears twice except for one. ...

  2. leetcode 136 137 Single Number

    题目描述(面试常考题) 借助了异或的思想 class Solution { public: int singleNumber(vector<int>& nums) { ; ; i ...

  3. Leetcode 136 137 260 SingleNumber I II III

    Leetccode 136 SingleNumber I Given an array of integers, every element appears twice except for one. ...

  4. leetcode 136. Single Number 、 137. Single Number II 、 260. Single Number III(剑指offer40 数组中只出现一次的数字)

    136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solu ...

  5. LeetCode(137) Single Number II

    题目 Given an array of integers, every element appears three times except for one. Find that single on ...

  6. 【LeetCode】137. Single Number II 解题报告(Python)

    [LeetCode]137. Single Number II 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/single- ...

  7. leetcode 136 Single Number, 260 Single Number III

    leetcode 136. Single Number Given an array of integers, every element appears twice except for one. ...

  8. LeetCode 136. Single Number(只出现一次的数字)

    LeetCode 136. Single Number(只出现一次的数字)

  9. [LeetCode] Number of Islands II 岛屿的数量之二

    A 2d grid map of m rows and n columns is initially filled with water. We may perform an addLand oper ...

随机推荐

  1. Discuz使用tools修复数据文件后,访问URL多出/source/plugin/tools,导致文章栏目无法访问

    今天我的婚嫁亲子网数据库出了点错误,于是就用dz官方的tool工具修复了以下,然后就发生了这个错误.. 本来频道页面的地址是:http://www.ifen8.com/article/ 结果自动跳转成 ...

  2. kafka.network.SocketServer分析

    当Kafka启动时,会启动这个SocketServer来接收客户端的连接,处理客户端请求,发送响应. 这个类的注释说明了这个socket server的结构 /** * An NIO socket s ...

  3. 【NGUI】屏幕自适应(不用UIStretch,用UIRoot)---------------good

    原地址:http://blog.csdn.net/lzhq1982/article/details/18814023 这篇文章是转载的,之前用UIStretch做屏幕自适应,但一直有两个硬伤让我难受, ...

  4. java内存模型 年轻代/年老代 持久区

    jvm中的年轻代 老年代 持久代 gc   虚拟机中的共划分为三个代:年轻代(Young Generation).老年代(Old Generation)和持久代(Permanent Generatio ...

  5. WPF中通过代码定义模板

    WPF中可以再XAML中定义模板,也可以通过C#代码定义模板,通过代码可能更清楚的看清其逻辑,而且代码的好处就是可以随时动态的去操作,而在XAML中定义的一般都是静态的. //控件呈现的显示内容1(这 ...

  6. JS复制对象

    CSSCommonJS.DeepCopy = function (json) { if (typeof json == 'number' || typeof json == 'string' || t ...

  7. linux下关于程序性能和系统性能的工具、方法

    观察性能/状态的方法:top free netstat /pro/目录下的信息 其中/pro/meminfo下的信息相当丰富 ------------------------------------- ...

  8. How to change data dir of mysql?

    # 1 copy orgin data dir of mysql to new one cp -R /var/lib/mysql /mysqldata chown mysql:mysql -R /my ...

  9. linux编译注解

    Linux kernel release 3.x <http://kernel.org/> These are the release notes for Linux version 3. ...

  10. 【HDOJ】4341 Gold miner

    分组01背包.在一条直线上的点归为一组. /* 4341 */ #include <iostream> #include <sstream> #include <stri ...