Linked List Sorting (链表)
Linked List Sorting (链表)
A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and
a Next pointer to the next structure. Now given a linked list, you are supposed to sort the structures according to their key values in increasing order.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive N (< 105) and an address of the head node, where N is the total
number of nodes in memory and the address of a node is a 5-digit positive integer. NULL is represented by -1.
Then N lines follow, each describes a node in the format:
Address Key Next
where Address is the address of the node in memory, Key is an integer in [-105, 105], and Next is the address of the next node. It is guaranteed that all
the keys are distinct and there is no cycle in the linked list starting from the head node.
Output Specification:
For each test case, the output format is the same as that of the input, where N is the total number of nodes in the list and all the nodes must be sorted
order.
Sample Input:
5 00001
11111 100 -1
00001 0 22222
33333 100000 11111
12345 -1 33333
22222 1000 12345
Sample Output:
5 12345
12345 -1 00001
00001 0 11111
11111 100 22222
22222 1000 33333
33333 100000 -1
坑点:1、可能是空链表 2、并不是每个节点都在链表上的
#include <iostream>
#include <vector>
#include<iomanip>
#include <algorithm>
using namespace std;
struct node
{
int add;
int data;
int next;
};
node a[100000],b[100000];
bool cmp(node n1,node n2)
{
return n1.data<n2.data;
}
int main()
{
int len,fir,add,data,next;
int i;
while(cin>>len)
{
cin>>fir;
for(i=0;i<len;i++)
{
cin>>add>>data>>next;
node n;
n.add=add;
n.data=data;
n.next=next;
a[add]=n;
}
if(fir==-1)
{
cout<<"0 -1"<<endl;
continue;
}
i=0;
while(fir!=-1)
{
b[i].add =a[fir].add;
b[i].data =a[fir].data;
b[i].next =a[fir].next;
fir = a[fir].next;
++i;
}
int len=i;
sort(b,b+len,cmp);
for(i=0;i<len-1;i++)
{
b[i].next=b[i+1].add;
}
b[len-1].next=-1;
cout<<len<<" "<<setfill('0')<<setw(5)<<b[0].add<<endl;
for(i=0;i<len;i++)
{
if(b[i].next==-1)
cout<<setfill('0')<<setw(5)<<b[i].add<<" "<<b[i].data<<" "<<-1<<endl;
else
cout<<setfill('0')<<setw(5)<<b[i].add<<" "<<b[i].data<<" "<<setfill('0')<<setw(5)<<b[i].next<<endl;
}
}
return 0;
}
Linked List Sorting (链表)的更多相关文章
- PAT 甲级 1052 Linked List Sorting (25 分)(数组模拟链表,没注意到不一定所有节点都在链表里)
1052 Linked List Sorting (25 分) A linked list consists of a series of structures, which are not ne ...
- PAT 解题报告 1052. Linked List Sorting (25)
1052. Linked List Sorting (25) A linked list consists of a series of structures, which are not neces ...
- PAT1052:Linked List Sorting
1052. Linked List Sorting (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A ...
- PAT 1052 Linked List Sorting [一般]
1052 Linked List Sorting (25 分) A linked list consists of a series of structures, which are not nece ...
- Pat 1052 Linked List Sorting (25)
1052. Linked List Sorting (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A ...
- pat1052. Linked List Sorting (25)
1052. Linked List Sorting (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A ...
- Linked List Sorting
静态链表(用结构体数组模拟链表) 1052 Linked List Sorting (25分) A linked list consists of a series of structur ...
- [CareerCup] 2.3 Delete Node in a Linked List 删除链表的节点
2.3 Implement an algorithm to delete a node in the middle of a singly linked list, given only access ...
- 【PAT】1052 Linked List Sorting (25)(25 分)
1052 Linked List Sorting (25)(25 分) A linked list consists of a series of structures, which are not ...
随机推荐
- javaEE学习笔记-利用DOM4J解析xml至数据库
xml代码文件名:test02.xml <ACCESOS> <item> <SOCIO> <NUMERO>00045050</NUMERO> ...
- 为Google Reader守夜。。。
Google的阅读器快要关闭了... 立刻截图留恋呢,以后就没机会了. 唉,真是令人惋惜. 虽然我接触Google Reader还不到一年,但是我已经习惯当连上WiFi时马上更新一下手机上的gRead ...
- [未完成]关于DOM的总结
这样有什么好处吗? 一但这些东西变成了节点对象,意味着每一个节点对象都会有很多属性和行为提供出来. 如果div是一个对象,那么就可以针对这个对象调用其中的一些方法,对div操作. 这个操作可以包括,比 ...
- JS的第一节课
javascript中有两个非常重要的数据类型是对象和数组. e.g: var book={ topic:"javascript", fat:true };
- ActiveMQ(5.10.0) - Wildcards and composite destinations
In this section we’ll look at two useful features of ActiveMQ: subscribing to multiple destinations ...
- Ehcache(2.9.x) - API Developer Guide, Cache Loaders
About Cache Loaders A CacheLoader is an interface that specifies load() and loadAll() methods with a ...
- Ehcache(2.9.x) - API Developer Guide, Cache Decorators
About Cache Decorators Ehcache uses the Ehcache interface, of which Cache is an implementation. It i ...
- 浅谈Oracle 性能优化
基于大型Oracle数据库应用开发已有6个年头了,经历了从最初零数据演变到目前上亿级的数据存储.在这个经历中,遇到各种各样的性能问题及各种性能优化. 在这里主要给大家分享一下数据库性能优化的一些方法和 ...
- 160多个android开源代码汇总
第一部分 个性化控件(View) 主要介绍那些不错个性化的View,包括ListView.ActionBar.Menu.ViewPager.Gallery.GridView.ImageView.Pro ...
- Android之布局
Android中的布局分为六种,分别是相对布局.线性布局.表格布局.网格布局.帧布局.绝对布局,良好的布局设计对UI界面至关重要,下面先来看看先相对布局. 相对布局(RelativeLayout): ...