Full Binary Tree(sdut 2882)
Problem Description:
Output
Sample Input
5
1 2
2 3
4 3
1024 2048
3214567 9998877
题解 只要找到公共节点即可,水题一个;
#include<stdio.h>
#include<string.h>
int main()
{
long long int i,j,a,b,m,n,p;
scanf("%lld",&p);
for(int k=;k<p;k++)
{
scanf("%lld%lld",&a,&b);
m=a>b?a:b;
n=a>b?b:a;
long long int count1=,count2=;
while(m!=n)
{
if(n>m)
n/=;
if(m==n)
break;
if(m>n)
m/=;
}//找到公共节点;
while(a!=m)
{
a/=;
count1++;
}
while(b!=m)
{
b/=;
count1++;
}//统计下每一节点到公共节点的距离
printf("%lld\n",count1); }
return ;
}
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