Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

Example:

Input: 38
Output: 2
Explanation: The process is like: 3 + 8 = 11, 1 + 1 = 2.
  Since 2 has only one digit, return it.

Follow up:
Could you do it without any loop/recursion in O(1) runtime?

 
class Solution(object):
def addDigits(self, num):
"""
:type num: int
:rtype: int
"""
s=str(num)
while len(s)>1:
n=0
for i in s:
n+=int(i)
s=str(n) return int(s)

  

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