【Oracle】查询执行慢的sql

查询执行最慢的sql

select *

from (select sa.SQL_TEXT,

sa.SQL_FULLTEXT,

sa.EXECUTIONS "执行次数",

round(sa.ELAPSED_TIME / 1000000, 2) "总执行时间",

round(sa.ELAPSED_TIME / 1000000 / sa.EXECUTIONS, 2) "平均执行时间",

sa.COMMAND_TYPE,

sa.PARSING_USER_ID "用户ID",

u.username "用户名",

sa.HASH_VALUE

from v$sqlarea sa

left join all_users u

on sa.PARSING_USER_ID = u.user_id

where sa.EXECUTIONS > 0

order by (sa.ELAPSED_TIME / sa.EXECUTIONS) desc)

where rownum <= 50;

查询次数最多的 sql

select *

from (select s.SQL_TEXT,

s.EXECUTIONS "执行次数",

s.PARSING_USER_ID "用户名",

rank() over(order by EXECUTIONS desc) EXEC_RANK

from v$sql s

left join all_users u

on u.USER_ID = s.PARSING_USER_ID) t

where exec_rank <= 100;

本文为头条号作者发布，不代表今日头条立场。

rank() over是的作用是查出指定条件后进行一个排名

转自：http://blog.csdn.net/u011277123/article/details/53943158