codeforces 644A Parliament of Berland
1 second
256 megabytes
standard input
standard output
There are n parliamentarians in Berland. They are numbered with integers from 1 to n. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republicans.
New parliament assembly hall is a rectangle consisting of a × b chairs — a rows of b chairs each. Two chairs are considered neighbouring if they share as side. For example, chair number 5 in row number 2is neighbouring to chairs number 4 and 6 in this row and chairs with number 5 in rows 1 and 3. Thus, chairs have four neighbours in general, except for the chairs on the border of the hall
We know that if two parliamentarians from one political party (that is two Democrats or two Republicans) seat nearby they spent all time discussing internal party issues.
Write the program that given the number of parliamentarians and the sizes of the hall determine if there is a way to find a seat for any parliamentarian, such that no two members of the same party share neighbouring seats.
The first line of the input contains three integers n, a and b (1 ≤ n ≤ 10 000, 1 ≤ a, b ≤ 100) — the number of parliamentarians, the number of rows in the assembly hall and the number of seats in each row, respectively.
If there is no way to assigns seats to parliamentarians in a proper way print -1.
Otherwise print the solution in a lines, each containing b integers. The j-th integer of the i-th line should be equal to the index of parliamentarian occupying this seat, or 0 if this seat should remain empty. If there are multiple possible solution, you may print any of them.
3 2 2
0 3
1 2
8 4 3
7 8 3
0 1 4
6 0 5
0 2 0
10 2 2
-1
In the first sample there are many other possible solutions. For example,
3 2
0 1
and
2 1
3 0
The following assignment
3 2
1 0
is incorrect, because parliamentarians 1 and 3 are both from Democrats party but will occupy neighbouring seats.
用1~n n个数填a*b的矩阵,要求奇数与奇数不相邻,偶数与偶数不相邻,如果a*b<n输出-1
#include<stdio.h>
#include<string.h>
#include<vector>
#include<map>
#include<queue>
#include<stack>
#include<cstdio>
#include<string>
#include<math.h>
#include<algorithm>
#define LL long long
#define PI atan(1.0)*4
#define II __int64
#define DD double
#define MAX 10010
#define mod 10003
#define INF 0x3f3f3f
using namespace std;
int s[110][110];
int main()
{
int t,n,m,a,b,i,j,k;
while(scanf("%d%d%d",&n,&a,&b)!=EOF)
{
if(a*b<n)
{
printf("-1\n");
continue;
}
memset(s,0,sizeof(s));
i=1;j=1;k=1;
for(i=1;i<=a;i++)
{ if(i&1)
for(j=1;j<=b;j++)
{
if(k>n) break;
s[i][j]=k++;
}
else
for(j=b;j>=1;j--)
{
if(k>n) break;
s[i][j]=k++;
}
if(k>n) break;
}
for(i=1;i<=a;i++)
{
for(j=1;j<=b;j++)
printf("%d ",s[i][j]);
printf("\n");
}
}
return 0;
}
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