https://leetcode.com/mockinterview/session/result/xsicjnm/

https://leetcode.com/problems/guess-number-higher-or-lower-ii/

// https://discuss.leetcode.com/topic/51353/simple-dp-solution-with-explanation
// https://en.wikipedia.org/wiki/Minimax
// 开始我的思路有问题,我是先选择区间,最后收敛到结果数
// 实际上work的思路是,先选择数字,再走向某个区间,然后取两个区间中的更大值 class Solution {
int ** table;
int DP(int s, int e) {
if (s >= e) {
return 0;
} if (table[s][e] != INT_MAX) {
return table[s][e];
}
int local_max = INT_MAX;
for (int k=s; k<=e; ++k) {
// 下面这个表达式很重要
local_max = min(k + max(DP(s, k-1), DP(k+1, e)), local_max);
}
table[s][e] = local_max;
return local_max;
} public:
int getMoneyAmount(int n) { table = new int*[n+1];
for (int i=0; i<n+1; ++i) {
table[i] = new int[n+1];
for (int j=0; j<n+1; ++j) {
table[i][j] = INT_MAX;
}
} int ret = DP(1, n); for (int i=0; i<n+1; ++i) {
delete[] table[i];
}
delete[] table; return ret;
} }; // 用Java又做了一遍 package com.company; import java.util.ArrayList;
import java.util.List; class Solution {
int[][] dp; int get(int s, int e) {
if (s >= e) {
// 注意,只有一个的话,不用猜
return 0;
} if (dp[s][e] != 0) {
return dp[s][e];
} // 注意Java的是这种形式的MIN/MAX
int min = Integer.MAX_VALUE;
for (int i=s; i<=e; i++) {
int tmp = Math.max(get(s, i-1), get(i+1, e)) + i;
if (tmp < min) {
min = tmp;
}
}
dp[s][e] = min;
return min;
} public int getMoneyAmount(int n) {
// 看了之前做的内容,思路还是很清晰的
// 要用DP的时候,不要犹豫 dp =new int[n+1][n+1];
int ret = get(1, n);
return ret;
}
} public class Main { public static void main(String[] args) {
// write your code here
System.out.println("Hello");
Solution solution = new Solution(); int ret = solution.getMoneyAmount(3);
System.out.printf("Get ret: %d\n", ret); }
}

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