Sql存储过程解密方法

在网上查到这样一个存储过程解密的方法，用起来简单，收藏到这里：

 CREATE     PROCEDURE   sp_decrypt_sp   (@objectName   varchar(50))
   AS
   ------------------------sql2000大于40000的-----------------
   --原作：j9988   号:J老师  

   begin   tran
   begin
   declare   @objectname1   varchar(100)
   declare   @sql1   nvarchar(4000),@sql2   nvarchar(4000),@sql3   nvarchar(4000),@sql4   nvarchar(4000),@sql5   nvarchar(4000),@sql6   nvarchar(4000),@sql7   nvarchar(4000),@sql8   nvarchar(4000),@sql9   nvarchar(4000),@sql10   nvarchar(4000)
   DECLARE     @OrigSpText1   nvarchar(4000),     @OrigSpText2   nvarchar(4000)   ,   @OrigSpText3   nvarchar(4000),   @resultsp   nvarchar(4000)
   declare     @i   int   ,   @t   bigint
   declare   @m   int,@n   int,@q   int
   set   @m=(SELECT   max(colid)   FROM   syscomments     WHERE   id   =   object_id(@objectName))
   set   @n=1
   --get   encrypted   data
   create   table     #temp(colid   int,ctext   varbinary(8000))
   insert   #temp   SELECT   colid,ctext   FROM   syscomments     WHERE   id   =   object_id(@objectName)
   set   @sql1='ALTER   PROCEDURE   '+   @objectName   +'   WITH   ENCRYPTION   AS   '
   --set   @sql1='ALTER   PROCEDURE   '+   @objectName   +'   WITH   ENCRYPTION   AS   '
   set   @q=len(@sql1)
   set   @sql1=@sql1+REPLICATE('-',4000-@q)
   select   @sql2=REPLICATE('-',4000),@sql3=REPLICATE('-',4000),@sql4=REPLICATE('-',4000),@sql5=REPLICATE('-',4000),@sql6=REPLICATE('-',4000),@sql7=REPLICATE('-',4000),@sql8=REPLICATE('-',4000),@sql9=REPLICATE('-',4000),@sql10=REPLICATE('-',4000)
   exec(@sql1+@sql2+@sql3+@sql4+@sql5+@sql6+@sql7+@sql8+@sql9+@sql10)
   while   @n<=@m
   begin
   SET   @OrigSpText1=(SELECT   ctext   FROM   #temp     WHERE   colid=@n)
   set   @objectname1=@objectname+'_t'
   SET   @OrigSpText3=(SELECT   ctext   FROM   syscomments   WHERE   id=object_id(@objectName)   and   colid=@n)
   if   @n=1
   begin
   SET   @OrigSpText2='CREATE   PROCEDURE   '+   @objectName   +'   WITH   ENCRYPTION   AS   '--
   set   @q=4000-len(@OrigSpText2)
   set   @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)
   end
   else
   begin
   SET   @OrigSpText2=REPLICATE('-',   4000)
   end
   --start   counter
   SET   @i=1
   --fill   temporary   variable
   SET   @resultsp   =   replicate(N'A',   (datalength(@OrigSpText1)   /   2))  

   --loop
   WHILE   @i<=datalength(@OrigSpText1)/2
   BEGIN
   --reverse   encryption   (XOR   original+bogus+bogus   encrypted)
   SET   @resultsp   =   stuff(@resultsp,   @i,   1,   NCHAR(UNICODE(substring(@OrigSpText1,   @i,   1))   ^
                                                                   (UNICODE(substring(@OrigSpText2,   @i,   1))   ^
                                                                   UNICODE(substring(@OrigSpText3,   @i,   1)))))
           SET   @i=@i+1
   END
   --drop   original   SP
   --EXECUTE   ('drop   PROCEDURE   '+   @objectName)
   --remove   encryption
   --preserve   case
   SET   @resultsp=REPLACE((@resultsp),'WITH   ENCRYPTION',   '')
   SET   @resultsp=REPLACE((@resultsp),'With   Encryption',   '')
   SET   @resultsp=REPLACE((@resultsp),'with   encryption',   '')
   IF   CHARINDEX('WITH   ENCRYPTION',UPPER(@resultsp)   )>0
       SET   @resultsp=REPLACE(UPPER(@resultsp),'WITH   ENCRYPTION',   '')
   --replace   Stored   procedure   without   enryption
   print   @resultsp
   --execute(   @resultsp)
   set   @n=@n+1
   end
   drop   table   #temp
   end
   rollback   tran
   --适合40000字符。
   --每次4000　print出来，自已贴。
   --切记：我见过的解过程都是对原过程进行破坏。破解前一定要备份!!!!
   --超过40000的，自已加SQL（我上面用SQL.SQL2－－SQL10）
   --超长的可加SQL11--sql20........  

   GO