ZOJ 3961 Let's Chat 【水】

题目链接

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3961

题意

给出两个人的发消息的记录，然后 如果有两人在连续M天及以上 互发消息，超过几天 加几点 友谊值 最后求 友谊值

思路

先把第一个 连续区间 >= M 的 存下来 然后第二次 输入的时候 去判断。

AC代码

#include <cstdio>
#include <cstring>
#include <ctype.h>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <stack>
#include <set>
#include <numeric>
#include <sstream>

using namespace std;
typedef long long LL;

const double PI = 3.14159265358979323846264338327;
const double E = 2.718281828459;
const double eps = 1e-6;

const int MAXN = 0x3f3f3f3f;
const int MINN = 0xc0c0c0c0;
const int maxn = 1e5 + 5;
const int MOD = 1e9 + 7;

int main()
{
    int t;
    scanf("%d", &t);
    while (t--)
    {
        int n, q;
        int i, j;
        scanf("%d%d", &n, &q);
        map <string, string> M;
        M.clear();
        string s, temp = "";
        for (i = 0; i < q; i++)
            temp += "0";
        int m;
        scanf("%d", &m);
        for (i = 0; i < m; i++)
        {
            cin >> s;
            M[s] = temp;
        }
        for (i = 0; i < q; i++)
        {
            scanf("%d", &m);
            for (j = 0; j < m; j++)
            {
                cin >> s;
                M[s][i] = '1';
            }
        }
//      map <string, string>::iterator it;
//      for (it = M.begin(); it != M.end(); it++)
//          cout << it -> first << " " << it -> second << endl;
        string ans;
        int num;
        for (i = 0; i < n; i++)
        {
            temp.clear();
            for (j = 0; j < q; j++)
            {
                scanf(" %d", &num);
                temp += num + '0';
            }
            int flag = 0;
            ans.clear();
            map <string, string>:: iterator it;
            for (it = M.begin(); it != M.end(); it++)
            {
                if (it -> second == temp )
                {
                    if (flag == 1)
                    {
                        flag = 0;
                        break;
                    }
                    else
                    {
                        flag = 1;
                        ans = it -> first;
                    }
                }
            }
            if (flag)
                cout << ans << endl;
            else
                printf("Let's go to the library!!\n");
        }
    }
}