AtCoder Beginner Contest 087 (ABC)
A - Buying Sweets
题目链接:https://abc087.contest.atcoder.jp/tasks/abc087_a
Time limit : 2sec / Memory limit : 256MB
Score : 100 points
Problem Statement
You went shopping to buy cakes and donuts with X yen (the currency of Japan).
First, you bought one cake for A yen at a cake shop. Then, you bought as many donuts as possible for B yen each, at a donut shop.
How much do you have left after shopping?
Constraints
- 1≤A,B≤1 000
- A+B≤X≤10 000
- X, A and B are integers.
Input
Input is given from Standard Input in the following format:
X
A
B
Output
Print the amount you have left after shopping.
Sample Input 1
1234
150
100
Sample Output 1
84
You have 1234−150=1084 yen left after buying a cake. With this amount, you can buy 10 donuts, after which you have 84 yen left.
Sample Input 2
1000
108
108
Sample Output 2
28
Sample Input 3
579
123
456
Sample Output 3
0
Sample Input 4
7477
549
593
Sample Output 4
405
#include<bits/stdc++.h>
using namespace std; int main()
{
int x,a,b;
while(cin>>x>>a>>b){
x-=a;
x%=b;
cout<<x<<endl;
}
return ;
}
B - Coins
题目链接:https://abc087.contest.atcoder.jp/tasks/abc087_b
Time limit : 2sec / Memory limit : 256MB
Score : 200 points
Problem Statement
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?
Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.
Constraints
- 0≤A,B,C≤50
- A+B+C≥1
- 50≤X≤20 000
- A, B and C are integers.
- X is a multiple of 50.
Input
Input is given from Standard Input in the following format:
A
B
C
X
Output
Print the number of ways to select coins.
Sample Input 1
2
2
2
100
Sample Output 1
2
There are two ways to satisfy the condition:
- Select zero 500-yen coins, one 100-yen coin and zero 50-yen coins.
- Select zero 500-yen coins, zero 100-yen coins and two 50-yen coins.
Sample Input 2
5
1
0
150
Sample Output 2
0
Note that the total must be exactly X yen.
Sample Input 3
30
40
50
6000
Sample Output 3
213
题解:找零钱
#include<bits/stdc++.h>
using namespace std; int main()
{
int x,a,b,c;
while(cin>>a>>b>>c>>x){
x/=;
int sum=;
for(int i=;i<=a;i++){
for(int j=;j<=b;j++){
for(int k=;k<=c;k++){
if(i*+j*+k==x) sum++;
}
}
}
cout<<sum<<endl;
}
return ;
}
C - Candies
题目链接:https://abc087.contest.atcoder.jp/tasks/arc090_a
Time limit : 2sec / Memory limit : 256MB
Score : 300 points
Problem Statement
We have a 2×N grid. We will denote the square at the i-th row and j-th column (1≤i≤2, 1≤j≤N) as (i,j).
You are initially in the top-left square, (1,1). You will travel to the bottom-right square, (2,N), by repeatedly moving right or down.
The square (i,j) contains Ai,j candies. You will collect all the candies you visit during the travel. The top-left and bottom-right squares also contain candies, and you will also collect them.
At most how many candies can you collect when you choose the best way to travel?
Constraints
- 1≤N≤100
- 1≤Ai,j≤100 (1≤i≤2, 1≤j≤N)
Input
Input is given from Standard Input in the following format:
N
A1,1 A1,2 … A1,N
A2,1 A2,2 … A2,N
Output
Print the maximum number of candies that can be collected.
Sample Input 1
5
3 2 2 4 1
1 2 2 2 1
Sample Output 1
14
The number of collected candies will be maximized when you:
- move right three times, then move down once, then move right once.
Sample Input 2
4
1 1 1 1
1 1 1 1
Sample Output 2
5
You will always collect the same number of candies, regardless of how you travel.
Sample Input 3
7
3 3 4 5 4 5 3
5 3 4 4 2 3 2
Sample Output 3
29
Sample Input 4
1
2
3
Sample Output 4
5 题解:分成两个数组 同时使用前缀和 取最大值
#include<bits/stdc++.h>
using namespace std;
int a[],b[];
int suma[],sumb[];
int main()
{
int n;
while(cin>>n){
for(int i=;i<n;i++){
cin>>a[i];
}
for(int i=;i<n;i++){
cin>>b[i];
}
suma[]=a[];sumb[]=b[];
for(int i=;i<n;i++){
suma[i]=suma[i-]+a[i];
sumb[i]=sumb[i-]+b[i];
}
int maxn=suma[]+sumb[n-];
for(int i=;i<n;i++){
int sum=suma[i]+sumb[n-]-sumb[i-];
maxn=max(maxn,sum);
}
cout<<maxn<<endl;
}
return ;
}
AtCoder Beginner Contest 087 (ABC)的更多相关文章
- AtCoder Beginner Contest 088 (ABC)
A - Infinite Coins 题目链接:https://abc088.contest.atcoder.jp/tasks/abc088_a Time limit : 2sec / Memory ...
- AtCoder Beginner Contest 050 ABC题
A - Addition and Subtraction Easy Time limit : 2sec / Memory limit : 256MB Score : 100 points Proble ...
- AtCoder Beginner Contest 087 D - People on a Line
Time limit : 2sec / Memory limit : 256MB Score : 400 points Problem Statement There are N people sta ...
- AtCoder Beginner Contest 087 B - Coins
Time limit : 2sec / Memory limit : 256MB Score : 200 points Problem Statement You have A 500-yen coi ...
- AtCoder Beginner Contest 087 D People on a Line(DFS)
题意 给出n个点,m组关系L,R,D,L在R的左边距离D,判断是否存在n个人的位置满足m组关系 分析 Consider the following directed graph G: There ar ...
- AtCoder Beginner Contest 100 2018/06/16
A - Happy Birthday! Time limit : 2sec / Memory limit : 1000MB Score: 100 points Problem Statement E8 ...
- AtCoder Beginner Contest 053 ABCD题
A - ABC/ARC Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Smeke has ...
- AtCoder Beginner Contest 076
A - Rating Goal Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Takaha ...
- AtCoder Beginner Contest 068 ABCD题
A - ABCxxx Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement This contes ...
随机推荐
- windows下安装Git安装
一:Git是什么? Git是一个代码仓库,属于分散型版本管理系统. 二:在windows下安装Git 载msysgit 1. 访问 msysGit 的项目主页,下载 msysGit.http://ms ...
- LVS集群简介及使用
什么是集群 一组通过高速网络互联的计算组,并以单一系统的模式加以管理 将很多服务器集中在一起,提供一种服务,在客户端看来就象是只有一个服务器 可以在付出较低成本的情况下获得在性能,可靠性,灵活性方面的 ...
- 013-程序性能分析之thread dump和heap dump
一.dump基本概念 主要用于故障定位(尤其是out of memory)和性能分析.主要记录了JVM运行期间的内存占用.线程执行等情况,这就是常说的dump文件.常用的有heap dump和thre ...
- Git的安装和配置用户名和密码
在Windows中进行安装.访问https://git-scm.com/,点击Downloads for Windows,我下载的是Git-2.16.2-64-bit.exe.都按照默认选项即可,其中 ...
- 图片在IE8浏览器多一个有边框问题解决办法
最后在网上找了一下答案,IE8浏览器图片多一个有色边框,而Chrome浏览器没有边框的解决办法. 指定img的边框样式: img{border-style:none;}
- Spark log4j日志配置详解(转载)
一.spark job日志介绍 spark中提供了log4j的方式记录日志.可以在$SPARK_HOME/conf/下,将 log4j.properties.template 文件copy为 l ...
- [wx]雪落香杉树人物关系图
雪落香杉树 开始的时候场面比较宏大,出场的人比较多.加上外国人名字没辨识度,所以容易乱 被告人: 宫本天道 9 10 11 12月被关77天(谋杀罪,9.16日早谋杀卡尔.海因)--妻子:初枝 白色衬 ...
- tf中的run()与eval()【转载】
转自:https://blog.csdn.net/jiaoyangwm/article/details/79248535 1.eval() 其实就是tf.Tensor的Session.run() 的 ...
- dialog问题记录
这个怎么回事,怎么会负利润 http://mmbiz.qpic.cn/mmbiz_jpg/sd9PceC1NdAEVpR5pKerugkpEPEUIsBVoaz5ibTiaHtxoickmF2bXqF ...
- 大数据工具比较:R 语言和 Spark 谁更胜一筹?
本文有两重目的,一是在性能方面快速对比下R语言和Spark,二是想向大家介绍下Spark的机器学习库 背景介绍 由于R语言本身是单线程的,所以可能从性能方面对比Spark和R并不是很明智的做法.即使这 ...