C. Bear and Prime 100
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

This is an interactive problem. In the output section below you will see the information about flushing the output.

Bear Limak thinks of some hidden number — an integer from interval [2, 100]. Your task is to say if the hidden number is prime or composite.

Integer x > 1 is called prime if it has exactly two distinct divisors, 1 and x. If integer x > 1 is not prime, it's called composite.

You can ask up to 20 queries about divisors of the hidden number. In each query you should print an integer from interval [2, 100]. The system will answer "yes" if your integer is a divisor of the hidden number. Otherwise, the answer will be "no".

For example, if the hidden number is 14 then the system will answer "yes" only if you print 2,7 or 14.

When you are done asking queries, print "prime" or "composite" and terminate your program.

You will get the Wrong Answer verdict if you ask more than 20 queries, or if you print an integer not from the range [2, 100]. Also, you will get the Wrong Answer verdict if the printed answer isn't correct.

You will get the Idleness Limit Exceeded verdict if you don't print anything (but you should) or if you forget about flushing the output (more info below).

Input

After each query you should read one string from the input. It will be "yes" if the printed integer is a divisor of the hidden number, and "no" otherwise.

Output

Up to 20 times you can ask a query — print an integer from interval [2, 100] in one line. You have to both print the end-of-line character and flush the output. After flushing you should read a response from the input.

In any moment you can print the answer "prime" or "composite" (without the quotes). After that, flush the output and terminate your program.

To flush you can use (just after printing an integer and end-of-line):

  • fflush(stdout) in C++;
  • System.out.flush() in Java;
  • stdout.flush() in Python;
  • flush(output) in Pascal;
  • See the documentation for other languages.

Hacking. To hack someone, as the input you should print the hidden number — one integer from the interval [2, 100]. Of course, his/her solution won't be able to read the hidden number from the input.

Examples
input
yes no yes
output
2 80 5 composite
input
no yes no no no
output
58 59 78 78 2 prime
Note

The hidden number in the first query is 30. In a table below you can see a better form of the provided example of the communication process.

The hidden number is divisible by both 2 and 5. Thus, it must be composite. Note that it isn't necessary to know the exact value of the hidden number. In this test, the hidden number is 30.

59 is a divisor of the hidden number. In the interval [2, 100] there is only one number with this divisor.

The hidden number must be 59, which is prime. Note that the answer is known even after the second query

and you could print it then and terminate. Though, it isn't forbidden to ask unnecessary queries (unless you exceed

the limit of 20 queries).

题意:系统给出一个除了一个数字(你不知道),你每次可以出一个数字,若这个数字是系统的数字的约数,则系统输出

yes否则输出no,你最多可以猜20次,要求在20次以内判定系统的数字是质数还是合数;

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <vector>
#include <queue>
#include <stack>
#include <map>
#include <algorithm>
#include <set>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
#define MM(a,b) memset(a,b,sizeof(a));
const double eps = 1e-10;
const int inf =0x7f7f7f7f;
const double pi=acos(-1);
int p2,q2,p1,ep,q1;
const int INF = 0x3f3f3f3f;
const int maxn = 1100;
int a[]={2,3,4,5,7,9,11,13,17,19,23,25,29,31,37,41,43,47,49};
char s[13];
int main()
{
int cnt=0;
for(int i=0;i<19;i++)
{
printf("%d\n",a[i]);
fflush(stdout);
scanf("%s",s);
if(s[0]=='y') cnt++;
if(cnt>=2) break;
}
if(cnt>=2) printf("composite\n");
else printf("prime\n");
return 0;
}

分析:题是水题,,但是输入输出是挂了,,看代码,,只要统计下2-50就好,因为>50的话,至少是2*m的

范围又是100,所以只要统计下<=50的,暴力打表一发

CF#356 div2 C 猜数字的更多相关文章

  1. C语言猜数字游戏

    猜数字游戏,各式各样的实现方式,我这边提供一个实现方式,希望可以帮到新手. 老程序猿就不要看了,黑呵呵 源代码1 include stdio.h include stdlib.h include ti ...

  2. 不一样的猜数字游戏 — leetcode 375. Guess Number Higher or Lower II

    好久没切 leetcode 的题了,静下心来切了道,这道题比较有意思,和大家分享下. 我把它叫做 "不一样的猜数字游戏",我们先来看看传统的猜数字游戏,Guess Number H ...

  3. java 猜数字游戏

    作用:猜数字游戏.随机产生1个数字(1~10),大了.小了或者成功后给出提示. 语言:java 工具:eclipse 作者:潇洒鸿图 时间:2016.11.10 >>>>> ...

  4. 【原创Android游戏】--猜数字游戏Version 0.1

    想当年高中时经常和小伙伴在纸上或者黑板上或者学习机上玩猜数字的游戏,在当年那个手机等娱乐设备在我们那还不是很普遍的时候是很好的一个消遣的游戏,去年的时候便写了一个Android版的猜数字游戏,只是当时 ...

  5. 【原创Android游戏】--猜数字游戏V1.1 --数据存储,Intent,SimpleAdapter的学习与应用

    --------------------------------------------------------------- V0.1版本 上次做完第一个版本后,发现还有一些漏洞,并且还有一些可以添 ...

  6. python学习笔记 ——python写的猜数字游戏 002

    from sys import exit import random def Arrfor(str): #CONTST = CONTST + 1 artificial = input("请输 ...

  7. Python小游戏之猜数字

    最近师兄师姐毕业,各种酒席,酒席上最常玩的一个游戏就是猜数字,游戏规则如下: 出题人在手机上输入一个0-100之间的数字,其它人轮流猜这个数字,如果你不幸猜中则要罚酒一杯.每次猜数字,出题人都要缩小范 ...

  8. 【Qt】2.4 做一个“猜数字”的游戏

    使用对话框和Qt设计师来实现一个相当简单的小游戏.同时将通过这个程序来看布局的隐藏和显示是如何来影响窗口界面的变化的. 新建一个Qt项目,把Qt Creator默认给的mainwindow.h.mai ...

  9. hihocoder 1169 猜数字

    传送门 时间限制:10000ms 单点时限:5000ms 内存限制:256MB 描述 你正在和小冰玩一个猜数字的游戏.小冰首先生成一个长为N的整数序列A1, A2, …, AN.在每一轮游戏中,小冰会 ...

随机推荐

  1. sublime text3 注册码 (Version 3.0)

    -– BEGIN LICENSE -– TwitterInc 200 User License EA7E-890007 1D77F72E 390CDD93 4DCBA022 FAF60790 61AA ...

  2. JavaScript更改css样式

    来源:https://www.w3school.com.cn/js/js_htmldom_css.asp 1, document.getElementById(id).style.property = ...

  3. golang强制类型转换

    github.com/Unknwon/com包的使用 package main import ( "fmt" "github.com/Unknwon/com" ...

  4. 批量操作checkbox

    通过post可获取选中的checkbox的value值,然后可以action到某一页面通过$_POST[]处理得到的checkbox的值,然后进行批量化增删改查等操作. // 关键性语句: <i ...

  5. 剑指Offer 1-41 代码(python实现)

    今天主要写了一下offer 1-41题,余下的稍后整理 1 """ 1 镜像二叉树: 递归 """ def mirror(root): if ...

  6. mysql-1.1基础

    笔记内容:mysql基础,创建数据库,创建表,操作数据表,操作数据,简单查询,条件查询,排序,分组,聚合,连接查询(等值连接,内连接,外链接),子查询 自己提示:脑图笔记存于网盘中  右键:新标签页打 ...

  7. 右键添加cmd notePad++快捷键

    1.将以下文字复制到txt文本,将txt修改为reg执行后,邮件菜单查. Windows Registry Editor Version 5.00 [HKEY_CLASSES_ROOT\Directo ...

  8. @RequestMapping-限定参数映射

    限定参数映射 测试:

  9. 二、redis学习(java操作redis缓存的工具jedis)

  10. linux复习5

    权限----------------- r //100 = 4 //文件 :读取内容, //文件夹:是查看文件夹的内容 w //文件 :写数据到文件 //文件夹:增删文件. //10 = 2 x // ...