ACM Registration system
Registration system
- 描述
-
A new e-mail service "Berlandesk" is going to be opened in Berland in the near future.
The site administration wants to launch their project as soon as possible, that's why they
ask you to help. You're suggested to implement the prototype of site registration system.
The system should work on the following principle.
Each time a new user wants to register, he sends to the system a request with his name.
If such a name does not exist in the system database, it is inserted into the database, and
the user gets the response OK, confirming the successful registration. If the name already
exists in the system database, the system makes up a new user name, sends it to the user
as a prompt and also inserts the prompt into the database. The new name is formed by the
following rule. Numbers, starting with 1, are appended one after another to name (name1,
name2, ...), among these numbers the least i is found so that namei does not yet exist in
the database.
- 输入
- The first line contains number n (1 ≤ n ≤ 105). The following n lines contain the requests to the system. Each request is a non-empty line, and consists of not more than 1000 characters, which are all lowercase Latin letters.
- 输出
- Print n lines, which are system responses to the requests: OK in case of successful registration, or a prompt with a new name, if the requested name is already taken.
- 样例输入
-
4
abacaba
acaba
abacaba
acab - 样例输出
-
OK
OK
abacaba1
OK#include <iostream>
#include <vector>
#include <string>
#include <map>
using namespace std; int main(){
int n;
cin >> n;
map<string,int> nameMap;
while(n--){
string str;
cin >>str;
if(nameMap.find(str)==nameMap.end()){
nameMap.insert(make_pair(str,));
cout<<"OK"<<endl;
}else{
nameMap[str]++;
cout<<str<<nameMap[str]<<endl;
}
}
}
ACM Registration system的更多相关文章
- (用了map) Registration system
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=93241#problem/C (654123) http://codeforces.com ...
- Codeforces Beta Round #4 (Div. 2 Only) C. Registration system hash
C. Registration system Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset ...
- c题 Registration system
Description A new e-mail service "Berlandesk" is going to be opened in Berland in the near ...
- CodeForces-4C Registration system
// Registration system.cpp : 此文件包含 "main" 函数.程序执行将在此处开始并结束. // #include <iostream> # ...
- nyoj Registration system
Registration system 时间限制:1000 ms | 内存限制:65535 KB 难度:2 描述 A new e-mail service "Berlandesk&q ...
- codeforces Registration system
Registration system A new e-mail service "Berlandesk" is going to be opened in Berland in ...
- Codeforces Beta Round #4 (Div. 2 Only) C. Registration system【裸hash/map】
C. Registration system time limit per test 5 seconds memory limit per test 64 megabytes input standa ...
- Registration system
Registration system 时间限制:1000 ms | 内存限制:65535 KB 难度:2 描写叙述 A new e-mail service "Berlandesk&q ...
- nyoj 911 Registration system(map)
Registration system 时间限制:1000 ms | 内存限制:65535 KB 难度:2 描述 A new e-mail service "Berlandesk&q ...
随机推荐
- DOM – 4.doucument属性
4.document属性 2.1 write 2.2 getElementById 方法 getElementsByName getElementsByTagName 案例:全选反选 案例:点击一个按 ...
- c#将http调用返回额json中的有关中文的unicode转换为中文(转)
转转地址:http://www.cnblogs.com/promise-7/archive/2012/11/05/2755515.html 中文转Unicode:HttpUtility.UrlEnco ...
- RecyclerView导入依赖包
1. eclipse 上的导入: 如下进入Android SDK的如下路径, \android-sdk\extras\android\m2repository\com\android\support\ ...
- 分佈式事務故障處理暨ORA-24756: transaction does not exist處理
ORA-24756处理 看到警告日誌一直報ORA-24756錯誤 Errors in file /oracle/admin/NHMIX01/bdump/nhmix01_reco_4959.trc: O ...
- web magic 小结
缘起 写了多年的程序,鲜有产出物,于是最近打算做个不可说的东西来祭奠逝去的青春.数据,是一个程序的起点,我们没有数以亿计的用户,无法让活跃用户给我们产生数据,那就只能去别人的站点上借点数据了.这个功能 ...
- HTML - DOCTYPE
HTML - DOCTYPE HTML 5 doctype <!DOCTYPE html> HTML4.01 Based on SGML. so the browser need the ...
- Oracle性能优化之SQL语句
1.SQL语句执行过程 1.1 SQL语句的执行步骤 1)语法分析,分析语句的语法是否符合规范,衡量语句中各表达式的意义. 2)语义分析,检查语句中涉及的所有数据库对象是否存在,且用户有相应的权限. ...
- Win10 UAP 绑定
Compiled DataBinding in Windows Universal Applications (UAP) http://nicksnettravels.builttoroam.com/ ...
- C语言中main函数的参数
转自:http://blog.csdn.net/cnctloveyu/article/details/3905720 我们经常用的main函数都是不带参数的.因此main 后的括号都是空括号.实际上, ...
- YAML 技术研究
YAML预研文档 YAML概要 YAML是"YAML Ain't a Markup Language"(YAML不是一种置标语言)的递归缩写,早先YAML的意思其实是:" ...