[ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.
The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.
One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.
The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."
Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!
Input Specification:
The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.
The last test case is followed by a line containing:
0 0
Output Specification:
For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:
Loowater is doomed!
Sample Input:
2 3
5
4
7
8
4
2 1
5
5
10
0 0
Output for Sample Input:
11
Loowater is doomed! 题目大意:输入n,m表示有n个头和m个勇士,接下来n个头的战斗力,m歌骑士的战斗力。规定一个骑士只能杀掉一个战斗力不大于其自身战斗力的头,同时要支付给他与战斗力等值的金币,问花费最少为多少,不能杀掉就显示样例2的输出。 解题思路:贪心,头和骑士能力从小到大排序,一个一个砍,不能砍掉当前头的骑士就不要。
#include<iostream>
#include<algorithm>
using namespace std;
int main(){
int n,m;
int heard[],power[];
while(cin>>n>>m){
if(n== && m==)return ;
for(int i=;i<n;i++)cin>>heard[i];
for(int j=;j<m;j++)cin>>power[j];
sort(heard,heard+n);
sort(power,power+m);
int cur=;
int cost=;
for(int i=;i<m;i++){//从小到大一个一个来砍,不能砍下当前的就不砍
if(power[i]>=heard[cur]){
cost+=power[i];
if(++cur == n)break;
}
}
if(cur<n)cout<<"Loowater is doomed!\n";
else cout<<cost<<'\n';
}return ;
}
[ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]的更多相关文章
- UVA 11292 Dragon of Loowater(简单贪心)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- uva 11292 Dragon of Loowater (勇者斗恶龙)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- [ACM_水题] UVA 12502 Three Families [2人干3人的活后分钱,水]
Three Families Three families share a garden. They usually clean the garden together at the end o ...
- UVa 11292 Dragon of Loowater (水题,排序)
题意:有n个条龙,在雇佣勇士去杀,每个勇士能力值为x,只能杀死头的直径y小于或等于自己能力值的龙,只能被雇佣一次,并且你要给x赏金,求最少的赏金. 析:很简单么,很明显,能力值高的杀直径大的,低的杀直 ...
- UVa 11292 - Dragon of Loowater(排序贪心)
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shore ...
- UVa 11292 Dragon of Loowater
简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> ...
- UVA - 11292 Dragon of Loowater 贪心
贪心策略:一个直径为X的头颅,应该让雇佣费用满足大于等于X且最小的骑士来砍掉,这样才能使得花费最少. AC代码 #include <cstdio> #include <cmath&g ...
- [ACM_水题] UVA 11729 Commando War [不可同时交代任务 可同时执行 最短完成全部时间 贪心]
There is a war and it doesn't look very promising for your country. Now it's time to act. You have a ...
- UVA它11292 - Dragon of Loowater
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
随机推荐
- 真机在wifi下调试android程序
大家好,最近在学习android程序由于手机接口问题,调试程序的时候老是接触不良而不能正常调试,因此感到相当苦恼,于是在网上查找无线调试android的方法.经过研究和尝试现已成功无线调试程序,方法分 ...
- ORACLE object_id和data_object_id
object_id和data_object_id 都是对象的唯一标识. object_id是对象的逻辑标识 data_object_id是对象的物理标识 对于没有物理存储的对象,data_object ...
- Git版本控制教程
Git 版本控制入门 不了解Git请查看权威Git书籍 ProGit(中文版). 一份很好的 Git 入门教程,点击这里查看. Git客户端下载地址: 官方Git - TortoiseGit - So ...
- libcore.io.GaiException: getaddrinfo failed: EAI_NODATA (No address associated with hostname)
log报错如下: Caused by: libcore.io.GaiException: getaddrinfo failed: EAI_NODATA (No address associated w ...
- Servlet实现重定向的两种方式
使用Servlet实现请求重定向:两种方式 1. response.setStatus(302); response.setHeader("location", "/Re ...
- 問題排查:行動裝置網頁前端 UI 設計 (1)
這是最近開始接手的一個微信公眾平台專案, 在重整後端程式碼時,因為也需要透過前端來看效果, 所以就因此在前端的部分遇到了不少問題, 畢竟這是以前沒接觸過的領域 (早年的網頁應用程式開發沒有那麼多分工) ...
- Odoo启动过程
[本文基于odoo9源码编写] odoo包含的服务有 db object report workflow web[wsgi] Odoo以wsgi 规范提供Web及Web服务db/object/repo ...
- Oracle primary,unique,foreign 区别,Hibernate 关联映射
Oracle primary,unique,foreign 区别 转:http://www.cnblogs.com/henw/archive/2012/08/15/2639510.html NOT N ...
- FreeBSD_11-系统管理——{Part_2-核心}
一.Managing Services in FreeBSD Service restart will only work if it is set to YES in /etc/rc.conf. T ...
- FreeBSD_11-系统管理——{Part_0-基础}
Tips: sysctl -d kern.maxvnodes #查看系统控制选项的含义 true > file #清空文件内容 alias ls 'ls -I(大写i)' #取消 root 的 ...