1027 Colors in Mars

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input Specification:

Each input file contains one test case which occupies a line containing the three decimal color values.

Output Specification:

For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.

Sample Input:

15 43 71

 

Sample Output:

#123456

题意：

　　给出三个数字将十进制数转化为13进制数字。

思路：

　　模拟。

Code：

 1 #include <bits/stdc++.h>
 2
 3 using namespace std;
 4
 5 int main() {
 6     int red, green, blue;
 7     cin >> red >> green >> blue;
 8     map<int, char> m;
 9     m[10] = 'A';
10     m[11] = 'B';
11     m[12] = 'C';
12     string ans = "#";
13     int x1 = red / 13;
14     if (x1 < 10)
15         ans += to_string(x1);
16     else
17         ans += m[x1];
18     int x2 = red % 13;
19     if (x2 < 10)
20         ans += to_string(x2);
21     else
22         ans += m[x2];
23     int y1 = green / 13;
24     if (y1 < 10)
25         ans += to_string(y1);
26     else
27         ans += m[y1];
28     int y2 = green % 13;
29     if (y2 < 10)
30         ans += to_string(y2);
31     else
32         ans += m[y2];
33     int z1 = blue / 13;
34     if (z1 < 10)
35         ans += to_string(z1);
36     else
37         ans += m[z1];
38     int z2 = blue % 13;
39     if (z2 < 10)
40         ans += to_string(z2);
41     else
42         ans += m[z2];
43     cout << ans << endl;
44     return 0;
45 }