c#实现golang 的channel

使用.NET的 BlockingCollection<T>来包装一个ConcurrentQueue<T>来实现golang的channel。

代码如下：

public class Channel<T>
{
    private BlockingCollection<T> _buffer;

    public Channel() : this() { }
    public Channel(int size)
    {
        _buffer = new BlockingCollection<T>(new ConcurrentQueue<T>(), size);
    }

    public bool Send(T t)
    {
        try
        {
            _buffer.Add(t);
        }
        catch (InvalidOperationException)
        {
            // will be thrown when the collection gets closed
            return false;
        }
        return true;
    }

    public bool Receive(out T val)
    {
        try
        {
            val = _buffer.Take();
        }
        catch (InvalidOperationException)
        {
            // will be thrown when the collection is empty and got closed
            val = default(T);
            return false;
        }
        return true;
    }

    public void Close()
    {
        _buffer.CompleteAdding();
    }

    public IEnumerable<T> Range()
    {
        T val;
        while (Receive(out val))
        {
            yield return val;
        }
    }
}

测试程序

[TestCase]
    public void TestSPSC_Performance()
    {
        int numItems = ;
        int numIterations = ;

        var stopWatch = new Stopwatch();
        stopWatch.Start();
        for (int i = ; i < numIterations; ++i)
        {
            var channel = new Channel<int>();
            var writer = Task.Factory.StartNew(() => { foreach (var num in Enumerable.Range(, numItems)) { channel.Send(num); } channel.Close(); });
            var reader = Task.Factory.StartNew<List<int>>(() => { var res = new List<int>(numItems); foreach (var num in channel.Range()) { res.Add(num); } return res; });
            Task.WaitAll(writer, reader);
        }
        stopWatch.Stop();

        var elapsedMs = stopWatch.Elapsed.TotalMilliseconds;
        Console.WriteLine("SPSC N = {0}: {1:.00}ms/iteration, {2:.00}ns/item (tx+rx)", numItems,  elapsedMs / numIterations, elapsedMs * 1000.0 / numItems / numIterations);
    }