python 判断列表的包含关系

def is_Sublist(l, s):
    sub_set = False
    if s == []:
        sub_set = True
    elif s == l:
        sub_set = True
    elif len(s) > len(l):
        sub_set = False  

    else:
        for i in range(len(l)):
            if l[i] == s[]:
                n =
                while (n < len(s)) and (l[i+n] == s[n]):
                    n +=   

                if n == len(s):
                    sub_set = True  

    return sub_set  

a = [,,,,]
b = [,]
c = [,]
print(is_Sublist(a, b))
print(is_Sublist(a, c))