【遍历二叉树】11把二叉树转换成前序遍历的链表【Flatten Binary Tree to Linked List】
本质上是二叉树的root->right->left遍历。
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
给定一个二叉树,就地的把他转换成一个链表。
例如:
给定
1
/ \
2 5
/ \ \
3 4 6
转换后的树应该向这样子:
1
\
2
\
3
\
4
\
5
\
6
提示:
如果你观察的足够仔细,你会发现,每个还在的右孩子指针指向了,这个节点在前序遍历中的后面的那个节点。
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
迭代版本:
test.cpp:
|
1
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 |
#include <iostream>
#include <cstdio> #include <stack> #include <vector> #include "BinaryTree.h" using namespace std; /** TreeNode *tmp; if (tmp->right) tmp->left = NULL; // 树中结点含有分叉, ConnectTreeNodes(pNodeA1, pNodeA2, pNodeA3); flatten(pNodeA1); TreeNode *trav = pNodeA1; DestroyTree(pNodeA1); |
递归版本:
test.cpp:
|
1
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 |
#include <iostream>
#include <cstdio> #include <stack> #include <vector> #include "BinaryTree.h" using namespace std; /** if(root == NULL) flatten(root->left); TreeNode *tmpright = root->right; return ; // 树中结点含有分叉, ConnectTreeNodes(pNodeA1, pNodeA2, pNodeA3); flatten(pNodeA1); TreeNode *trav = pNodeA1; DestroyTree(pNodeA1); |
结果输出:
6 7 1 4 3 5 2
|
1
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 |
#ifndef _BINARY_TREE_H_
#define _BINARY_TREE_H_ struct TreeNode TreeNode *CreateBinaryTreeNode(int value); #endif /*_BINARY_TREE_H_*/ |
|
1
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 |
#include <iostream>
#include <cstdio> #include "BinaryTree.h" using namespace std; /** //创建结点 return pNode; //连接结点 //打印节点内容以及左右子结点内容 if(pNode->left != NULL) if(pNode->right != NULL) printf("\n"); //前序遍历递归方法打印结点内容 if(pRoot != NULL) if(pRoot->right != NULL) void DestroyTree(TreeNode *pRoot) delete pRoot; DestroyTree(pLeft); |
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