本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90678474

1100 Mars Numbers (20 分)
 

People on Mars count their numbers with base 13:

  • Zero on Earth is called "tret" on Mars.
  • The numbers 1 to 12 on Earth is called "jan, feb, mar, apr, may, jun, jly, aug, sep, oct, nov, dec" on Mars, respectively.
  • For the next higher digit, Mars people name the 12 numbers as "tam, hel, maa, huh, tou, kes, hei, elo, syy, lok, mer, jou", respectively.

For examples, the number 29 on Earth is called "hel mar" on Mars; and "elo nov" on Mars corresponds to 115 on Earth. In order to help communication between people from these two planets, you are supposed to write a program for mutual translation between Earth and Mars number systems.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<). Then N lines follow, each contains a number in [0, 169), given either in the form of an Earth number, or that of Mars.

Output Specification:

For each number, print in a line the corresponding number in the other language.

Sample Input:

4
29
5
elo nov
tam

Sample Output:

hel mar
may
115
13

题目大意:火星人用13进制计数,把地球的十进制与火星的13进制相互转换,需要注意的是火星人的数字是字符形式。

思路:映射火星人的数字与字符,用string存储读取的一整行数据,要调用getline()函数,它会读取一行里包括空格在内的所有字符。注意一下火星人的数字超过13时,0~12映射的字符也会变化,需要加入判断~

 #include <iostream>
#include <string>
#include <map>
using namespace std;
string Earth_Mars[] = { "tret",
"jan","feb","mar","apr","may","jun","jly","aug","sep","oct","nov","dec",
"tam","hel","maa","huh","tou","kes","hei","elo","syy","lok","mer","jou" };
map <string, int> Mars_Earth;
void init();
void earthToMars(string &s);
void marsToEarth(string &s);
int main()
{
init();
int N;
scanf("%d", &N);
getchar();
for (int i = ; i < N; i++) {
string s;
getline(cin, s);
if (s[] >= '' && s[] <= '')
earthToMars(s);
else
marsToEarth(s);
}
return ;
}
void marsToEarth(string &s) {
if (s == "tret") {
cout << Mars_Earth[s] << endl;
return;
}
int size = s.size();
if (size < )
cout << Mars_Earth[s] << endl;
else {
string s1 = s.substr(, ),
s2 = s.substr(, );
cout << Mars_Earth[s1] + Mars_Earth[s2] << endl;
}
}
void earthToMars(string &s) {
int earth = ;
for (int i = ; i < s.length(); i++)
earth = earth * + s[i] - '';
if (earth <= ) {
cout << Earth_Mars[earth] << endl;
return;
}
else if (earth % == ) {
cout << Earth_Mars[earth / + ] << endl;
return;
}
string mars[];
mars[] = Earth_Mars[earth % ];
earth = earth / ;
mars[] = Earth_Mars[earth + ];
cout << mars[] << " " << mars[] << endl;
}
void init() {
for (int i = ; i < ; i++)
Mars_Earth[Earth_Mars[i]] = i;
for (int i = ; i < ; i++)
Mars_Earth[Earth_Mars[i]] = (i - ) * ;
}

PAT甲级——1100 Mars Numbers (字符串操作、进制转换)的更多相关文章

  1. C语言拼接字符串以及进制转换

    #include<stdio.h> #include<stdlib.h> #include<string.h> char *join1(char *, char*) ...

  2. PAT A1010 Radix (25 分)——进制转换,二分法

    Given a pair of positive integers, for example, 6 and 110, can this equation 6 = 110 be true? The an ...

  3. PAT甲级——A1100 Mars Numbers

    People on Mars count their numbers with base 13: Zero on Earth is called "tret" on Mars. T ...

  4. 总结day3 ---- 进制转换,字符串切片,字符串常用方法.,for 循环,

    前情提要: int 的相关操作 进制转换 bit_lenth() str 的索引,以及常用的相关方法 for 循环 索引 切片 相关方法 一  : int 的相关操作 int 主要用于生活中的计算问题 ...

  5. 1100 Mars Numbers——PAT甲级真题

    1100 Mars Numbers People on Mars count their numbers with base 13: Zero on Earth is called "tre ...

  6. PAT 1100 Mars Numbers[难]

    1100 Mars Numbers (20 分) People on Mars count their numbers with base 13: Zero on Earth is called &q ...

  7. pat 1100 Mars Numbers(20 分)

    1100 Mars Numbers(20 分) People on Mars count their numbers with base 13: Zero on Earth is called &qu ...

  8. PAT甲级 进制转换题_C++题解

    进制转换题 PAT (Advanced Level) Practice 进制转换题 目录 <算法笔记> 重点摘要 1015 Reversible Primes (20) 1019 Gene ...

  9. 1100 Mars Numbers

    题意:进制转换. 思路:注意当数字是13的倍数时,只需高位叫法的单词.比如26,是“hel”,而不是“hel tret”.我被坑在这里了!对应语句1的处理.另外,在输入n和n个字符串之间需要一个吸收字 ...

随机推荐

  1. 【遍历二叉树】01二叉树的前序遍历【Binary Tree Preorder Traversal】

    ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 给定一个二叉树,返回他的前序遍历的 ...

  2. H264 NALU 使用PS封装 RTP发送

    最近由于项目平台需求,要将H264 NALU封装为PS再用RTP发送,PS封装按照ISO DEC-13818-1标准.一个PS包包含PS Header, PES Header, PS system h ...

  3. ACM学习历程—CSU 1216 异或最大值(xor && 贪心 && 字典树)

    题目链接:http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1216 题目大意是给了n个数,然后取出两个数,使得xor值最大. 首先暴力枚举是C(n,  ...

  4. POJ1456:Supermarket

    浅谈堆:https://www.cnblogs.com/AKMer/p/10284629.html 题目传送门:http://poj.org/problem?id=1456 把物品按照时间排序,显然\ ...

  5. mac下安装node

    学着使用homebrew进行安装,发现很是方便. homebrew是mac下的一款管理安装的工具. 1. 安装homebrew 使用mac自带的ruby下载安装: ruby -e "$(cu ...

  6. 问题:C# params类型参数;结果:C#的参数类型:params、out和ref

    C#的参数类型:params.out和ref PS:由于水平有限,难免会有错误和遗漏,欢迎各位看官批评和指正,谢谢~ 首先回顾一下C#声明一个方法的语法和各项元素,[]代表可选 [访问修饰符] 返回值 ...

  7. WEB 项目中的全局异常处理

    在web 项目中,遇到异常一般有两种处理方式:try.....catch....:throw 通常情况下我们用try.....catch.... 对异常进行捕捉处理,可是在实际项目中随时的进行异常捕捉 ...

  8. USACO-Friday the Thirteenth(黑色星期五)-Section1.2<3>

    [英文原题] Friday the Thirteenth Is Friday the 13th really an unusual event? That is, does the 13th of t ...

  9. 谁是Docker的开发者

    由CHRIS DAWSON发表在thenewstack/DATA RESEARCH qianhen123/CHB译 我们分析了Docker的容器库并提出两个问题: 1.Docker的贡献者们感兴趣的其 ...

  10. Material使用09 MdCheckboxModule、MdMenuModule、MdTooltipModule

    1 MdCheckboxModule的使用 md-checkbox 实现的功能和  <input type="checkbox">  相同,只不过 md-checkbo ...