如何在cuda内核函数中产生随机数（host端调用，device端产生）

最近，需要在kernel函数中调用浮点型的随机数。于是上网搜了下相关资料，一种方式是自己手动写一个随机数的__device__函数，然后在调用的时候调用这个函数。另一种，原来cuda在toolkit中给出了实现方式。

首先要用到三个函数：

curandCreateGenerator(&gen,CURAND_RNG_PSEUDO_DEFAULT); 

指定触发器为gen，随机方式为CURAND_RNG_PSEUDO_DEFAULT

curandSetPseudoRandomGeneratorSeed(gen,1234ULL);

指定种子为1234ULL(不同的种子产生的随机数列是不一样的)

curandGenerateUniform(gen,devData,n);

根据触发器gen，输出目标指针为devData，规模大小为n

/*
 * This program uses the host CURAND API to generate 100
 * pseudorandom floats.
 */
#include <stdio.h>
#include <stdlib.h>
#include <cuda.h>
#include <curand.h>

#define CUDA_CALL(x) do { if((x)!=cudaSuccess) { \
    printf("Error at %s:%d\n",__FILE__,__LINE__);\
    return EXIT_FAILURE;}} while()
#define CURAND_CALL(x) do { if((x)!=CURAND_STATUS_SUCCESS) { \
    printf("Error at %s:%d\n",__FILE__,__LINE__);\
    return EXIT_FAILURE;}} while()

int main(int argc, char *argv[])
{
    size_t n = ;
    size_t i;
    curandGenerator_t gen;
    float *devData, *hostData;

    /* Allocate n floats on host */
    hostData = (float *)calloc(n, sizeof(float));

    /* Allocate n floats on device */
    CUDA_CALL(cudaMalloc((void **)&devData, n*sizeof(float)));

    /* Create pseudo-random number generator */
    CURAND_CALL(curandCreateGenerator(&gen,
                CURAND_RNG_PSEUDO_DEFAULT));

    /* Set seed */
    CURAND_CALL(curandSetPseudoRandomGeneratorSeed(gen,
                1234ULL));

    /* Generate n floats on device */
    CURAND_CALL(curandGenerateUniform(gen, devData, n));

    /* Copy device memory to host */
    CUDA_CALL(cudaMemcpy(hostData, devData, n * sizeof(float),
        cudaMemcpyDeviceToHost));

    /* Show result */
    for(i = ; i < n; i++) {
        printf("%1.4f ", hostData[i]);
    }
    printf("\n");

    /* Cleanup */
    CURAND_CALL(curandDestroyGenerator(gen));
    CUDA_CALL(cudaFree(devData));
    free(hostData);
    return EXIT_SUCCESS;
}

样例输出后，产生的结果为：（待补）