Hibernate 参数匹配查询

　　第一种：

public User validate(String userName, String password) {
    String hql = "from User where userName =:userName and password =:password";
    User user = null;
    Object[] values = {userName, password};
    String[] paramNames = {"userName", "password"};
    List<User> list = ht.findByNamedParam(hql, paramNames, values);
    if (list.size()!=){
        user = list.get();
    }
    return user;
}

　　第二种：

public User validate(String userName, String password) {
    String hql = "from User u where u.userName = ? and u.password = ?";
    User user = null;
    List<User> list = ht.find(hql, new Object[]{userName, password});
    if (list.size()!=){
        user = list.get();
    }
    return user;
}

　　两种方法：find() 和 findByNameParam()，from User u ...... u可写可不写

总结：

　　当用"?"的时候，必须 ht.***("", new Object(*));  否则会出现异常：org.hibernate.QueryParameterException: Position beyond number of declared ordinal parameters. Remember that ordinal parameters are 1-based! Position: 1

　　当用"=:"的时候，必须定义参数 parameters，values。ht.***("", parameters, values);

 hqlBuilder.addWhereClause(" 1=2 ", new Object[]{});//正常

 hqlBuilder.addWhereClause(" 1=2 ", ""});//报错

　　主要是知道报这个异常（org.hibernate.QueryParameterException: Position beyond number of declared ordinal parameters.）的解决方案。