题意:

输入一个正整数N和M(N<=1e5,M<=1e8),接下来输入N个正整数(<=1e3),按照升序输出"i-j",i~j的和等于M或者是最小的大于M的数段。

AAAAAccepted code:

 #define HAVE_STRUCT_TIMESPEC
#include<bits/stdc++.h>
using namespace std;
int a[];
int sum[];
vector<pair<int,int> >ans;
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n,m;
cin>>n>>m;
for(int i=;i<=n;++i){
cin>>a[i];
sum[i]=sum[i-]+a[i];
}
int l=,t=,mn=1e9;
for(int i=;i<=n;++i){
t-=a[i];
while(t<m&&l<=n)
t+=a[l++];
if(t>=m&&t<mn){
mn=t;
ans.clear();
ans.push_back({i+,l-});
}
else if(t==mn)
ans.push_back({i+,l-});
}
cout<<ans[].first<<"-"<<ans[].second;
for(int i=;i<ans.size();++i)
cout<<"\n"<<ans[i].first<<"-"<<ans[i].second;
return ;
}

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