According to Wikipedia:

Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. At each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.

Heap sort divides its input into a sorted and an unsorted region, and it iteratively shrinks the unsorted region by extracting the largest element and moving that to the sorted region. it involves the use of a heap data structure rather than a linear-time search to find the maximum.

Now given the initial sequence of integers, together with a sequence which is a result of several iterations of some sorting method, can you tell which sorting method we are using?

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then in the next line, N integers are given as the initial sequence. The last line contains the partially sorted sequence of the N numbers. It is assumed that the target sequence is always ascending. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print in the first line either "Insertion Sort" or "Heap Sort" to indicate the method used to obtain the partial result. Then run this method for one more iteration and output in the second line the resuling sequence. It is guaranteed that the answer is unique for each test case. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input 1:

10

3 1 2 8 7 5 9 4 6 0

1 2 3 7 8 5 9 4 6 0

Sample Output 1:

Insertion Sort

1 2 3 5 7 8 9 4 6 0

Sample Input 2:

10

3 1 2 8 7 5 9 4 6 0

6 4 5 1 0 3 2 7 8 9

Sample Output 2:

Heap Sort

5 4 3 1 0 2 6 7 8 9

#include<iostream>
using namespace std;
int main(){
int N; cin>>N;
int i,j,flag=1,tag=0;
int num0[N],num1[N];
for(i=0;i<N;i++)
cin>>num0[i];
for(i=0;i<N;i++)
cin>>num1[i];
for(i=0;i<N-1;i++)
if(num1[i]>num1[i+1]) break;
for(j=i+1;j<N;j++)
if(num1[j]!=num0[j]) flag=0;
if(flag==0){
cout<<"Heap Sort"<<endl;
for(j=1;j<N;j++)
if(num1[(j-1)/2]<num1[j]) break;
j=j-1;
int temp=num1[j];
num1[j]=num1[0];
num1[0]=temp;
j--;
int parent,child;
temp=num1[0];
for(parent=0;2*parent+1<=j;parent=child){
child=parent*2+1;
if(child<j&&num1[child+1]>num1[child])
child++;
if(num1[child]>temp)
num1[parent]=num1[child];
else
break;
}
num1[parent]=temp;
}
else{
cout<<"Insertion Sort"<<endl;
int temp=num1[i+1];
for(i=i+1;i>0;i--)
if(num1[i-1]>temp) num1[i]=num1[i-1];
else break;
num1[i]=temp;
}
for(int k=0;k<N;k++)
if(tag++==0) cout<<num1[k];
else cout<<" "<<num1[k];
return 0;
}

PAT 1098. Insertion or Heap Sort的更多相关文章

  1. PAT甲级1098. Insertion or Heap Sort

    PAT甲级1098. Insertion or Heap Sort 题意: 根据维基百科: 插入排序迭代,消耗一个输入元素每次重复,并增加排序的输出列表.在每次迭代中,插入排序从输入数据中删除一个元素 ...

  2. PAT甲级——1098 Insertion or Heap Sort (插入排序、堆排序)

    本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90941941 1098 Insertion or Heap So ...

  3. pat 甲级 1098. Insertion or Heap Sort (25)

    1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...

  4. 1098 Insertion or Heap Sort——PAT甲级真题

    1098 Insertion or Heap Sort According to Wikipedia: Insertion sort iterates, consuming one input ele ...

  5. 1098 Insertion or Heap Sort

    1098 Insertion or Heap Sort (25 分) According to Wikipedia: Insertion sort iterates, consuming one in ...

  6. PAT (Advanced Level) Practise - 1098. Insertion or Heap Sort (25)

    http://www.patest.cn/contests/pat-a-practise/1098 According to Wikipedia: Insertion sort iterates, c ...

  7. PAT (Advanced Level) 1098. Insertion or Heap Sort (25)

    简单题.判断一下是插排还是堆排. #include<cstdio> #include<cstring> #include<cmath> #include<ve ...

  8. PAT甲题题解1098. Insertion or Heap Sort (25)-(插入排序和堆排序)

    题目就是给两个序列,第一个是排序前的,第二个是排序中的,判断它是采用插入排序还是堆排序,并且输出下一次操作后的序列. 插入排序的特点就是,前面是从小到大排列的,后面就与原序列相同. 堆排序的特点就是, ...

  9. 【PAT甲级】1098 Insertion or Heap Sort (25 分)

    题意: 输入一个正整数N(<=100),接着输入两行N个数,表示原数组和经过一定次数排序后的数组.判断是经过插入排序还是堆排序并输出再次经过该排序后的数组(数据保证答案唯一). AAAAAcce ...

随机推荐

  1. HDU 5489 Difference of Clustering 图论

    Difference of Clustering Problem Description Given two clustering algorithms, the old and the new, y ...

  2. Office 修改语言

  3. 洛谷 P3377 模板左偏树

    题目:https://www.luogu.org/problemnew/show/P3377 左偏树的模板题: 加深了我对空 merge 的理解: 结构体的编号就是原序列的位置. 代码如下: #inc ...

  4. IJ:IJ笔记1

    ylbtech-IJ:IJ笔记1 1. 下拉框返回顶部 1. <form:select id="type" path="baseId" class=&qu ...

  5. 设计模式(二):单例模式(DCL及解决办法)

    public class Singleton { //懒汉模式 双重检查锁定DCL(double-checked locking) //缺点:由于jvm存在乱序执行功能,DCL也会出现线程不安全的情况 ...

  6. Linux基本命令 文件管理 下部

    1.1 移动文件 将/data目录移动到/root下 涉及命令mv [root@oldboyedu-50 ~]# mv /data/ /root/ 移动 [root@oldboyedu-50 ~]# ...

  7. SpringBoot集成CAS单点登录,SSO单点登录,CAS单点登录(视频资料分享篇)

    单点登录(Single Sign On),简称为 SSO,是目前比较流行的企业业务整合的解决方案之一.SSO的定义是在多个应用系统中,用户只需要登录一次就可以访问所有相互信任的应用系统. 很早期的公司 ...

  8. C/C++常用头文件 以及简单应用介绍

    C/C++头文件一览 C #include <assert.h> //设定插入点#include <ctype.h> //字符处理#include <errno.h> ...

  9. python中set元素为可迭代元素相加

    #a 与 b必须是两个相同类型的可迭代对象 a = "1" b = "2" print(set(a + b))  # {'1', '2'} a = " ...

  10. 【BZOJ4241】历史研究(回滚莫队)

    题目: BZOJ4241 分析: 本校某些julao乱膜的时候发明了个"回滚邹队",大概意思就是某个姓邹的太菜了进不了省队回滚去文化课 回滚莫队裸题qwq(话说这个名字是不是莫队本 ...