Rails_via牛客网
题目
链接:https://ac.nowcoder.com/acm/contest/28537/D
来源:牛客网时间限制:C/C++ 1秒,其他语言2秒
空间限制:C/C++ 32768K,其他语言65536K
64bit IO Format: %lld题目描述
There is a famous railway station in PopPush City. Country there is incredibly hilly. The station was built in last century. Unfortunately, funds were extremely limited that time. It was possible to establish only a surface track. Moreover, it turned out that the station could be only a dead-end one (see picture) and due to lack of available space it could have only one track.
The local tradition is that every train arriving from the direction A continues in the direction B with coaches reorganized in some way. Assume that the train arriving from the direction A has N <= 1000 coaches numbered in increasing order 1, 2, …, N. The chief for train reorganizations must know whether it is possible to marshal coaches continuing in the direction B so that their order will be a1, a2, …, aN. Help him and write a program that decides whether it is possible to get the required order of coaches. You can assume that single coaches can be disconnected from the train before they enter the station and that they can move themselves until they are on the track in the direction B. You can also suppose that at any time there can be located as many coaches as necessary in the station. But once a coach has entered the station it cannot return to the track in the direction A and also once it has left the station in the direction B it cannot return back to the station.
Input
The input consists of blocks of lines. Each block except the last describes one train and possibly more requirements for its reorganization. In the first line of the block there is the integer N described above. In each of the next lines of the block there is a permutation of 1, 2, …, N. The last line of the block contains just 0.The last block consists of just one line containing 0.
输入描述:
The input consists of blocks of lines. Each block except the last describes one train and possibly more requirements for its reorganization. In the first line of the block there is the integer N described above. In each of the next lines of the block there is a permutation of 1, 2, ..., N. The last line of the block contains just 0.
The last block consists of just one line containing 0.
输出描述:
The output contains the lines corresponding to the lines with permutations in the input. A line of the output contains Yes if it is possible to marshal the coaches in the order required on the corresponding line of the input. Otherwise it contains No. In addition, there is one empty line after the lines corresponding to one block of the input. There is no line in the output corresponding to the last ``null'' block of the input.
示例1
输入
5
1 2 3 4 5
5 4 1 2 3
0
6
6 5 4 3 2 1
0
0
输出
Yes
No Yes
题解
这道题目其实不难,重点是输入以及输出有大大的问题
代码
#include <iostream>
#include <stack>
using namespace std;
int s[1005];
int n = 0;
bool check()
{
int j = 0;
stack<int> a;
for (int i = 1; i <= n; i++)
{
a.push(i);
while (!a.empty() && a.top() == s[j])
{
a.pop();
j++;
}
}
if (a.empty())
{
return true;
}
else
return false;
}
int main()
{
int flags = 0;
int buf = 0;
while (1)
{
cin >> buf;
if (!buf)
break;
else
{
n = buf;
if (flags)
cout << endl;
}
while (1)
{
cin >> buf;
if (buf)
{
s[0] = buf;
for (int i = 1; i < n; i++)
cin >> s[i];
flags = 1;
if (check())
cout << "Yes" << endl;
else
cout << "No" << endl;
}
else
break;
}
}
return 0;
}
Rails_via牛客网的更多相关文章
- 牛客网 --java问答题
http://www.nowcoder.com/ 主要是自己什么都不怎么会.在这里可以学习很多的! 第一天看题自己回答,第二天看牛客网的答案! 1 什么是Java虚拟机?为什么Java被称作是“平台无 ...
- 牛客网《BAT面试算法精品课》学习笔记
目录 牛客网<BAT面试算法精品课>学习笔记 牛客网<BAT面试算法精品课>笔记一:排序 牛客网<BAT面试算法精品课>笔记二:字符串 牛客网<BAT面试算法 ...
- C++版 - HDUoj 2010 3阶的水仙花数 - 牛客网
版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C++版 - ...
- 牛客网第9场多校E(思维求期望)
链接:https://www.nowcoder.com/acm/contest/147/E 来源:牛客网 题目描述 Niuniu likes to play OSU! We simplify the ...
- 牛客网暑期ACM多校训练营(第七场)Bit Compression
链接:https://www.nowcoder.com/acm/contest/145/C 来源:牛客网 题目描述 A binary string s of length N = 2n is give ...
- Beautiful Numbers(牛客网)
链接:https://ac.nowcoder.com/acm/problem/17385来源:牛客网 题目描述 NIBGNAUK is an odd boy and his taste is stra ...
- 牛客网华为机试题之Python解法
牛客网华为机试题之Python解法 第1题 字符串最后一个单词的长度 a = input().split(" ") print(len(a[-1])) 第2题 计算字符个数 a = ...
- 牛客网Wannafly挑战赛25A 因子(数论 素因子分解)
链接:https://www.nowcoder.com/acm/contest/197/A来源:牛客网 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 262144K,其他语言5242 ...
- 牛客网 2018年东北农业大学春季校赛 L题 wyh的天鹅
链接:https://www.nowcoder.com/acm/contest/93/L来源:牛客网 时间限制:C/C++ 3秒,其他语言6秒空间限制:C/C++ 262144K,其他语言524288 ...
随机推荐
- 忘带U盘了??别急!一行python代码即可搞定文件传输
近日发现了python一个很有趣的功能,今天在这里给大伙儿做一下分享 需求前提 1.想要拷贝电脑的文件到另一台电脑但是又没有U盘2.手机上想获取到存储在电脑的文件3.忘带U盘- 您也太丢三落四了吧,但 ...
- goland设置import规范
import 规范 引入了三种类型的包,标准库包,第三方包,程序内部包,建议采用如下方式进行组织你的包: 有顺序的引入包,不同的类型采用空格分离, 第一种标准库 第二是第三方包 第三是项目包. 在项目 ...
- git提交代码到GitHub操作-简易版(后续完善)
一.git上传代码到GitHub 1.远程仓库GitHub创建好一个新仓库注意仓库名 2.本地建一个目录写代码,目录名与仓库命名一致 3.在目录下右键 git Bash here 打开git终端命令行 ...
- ucontext的简单介绍
简介 结构体 函数 getcontext setcontext makecontext swapcontext 简介 ucontext.h是GNU C库的一个头文件,主要用于用户态下的上下文切换.需要 ...
- IDEA找不到类但实际存在的问题解决
不知道某天开始Idea就开始抽风了. 现象: 一个service的接口类,就在同一个包下,但总是找不到,编辑器一直标红 编译可以通过 说明类本身应该是没什么问题的.问题是怎么重新编译重新reload ...
- 一分钟学会如何自定义小程序轮播图(蜜雪冰城Demo)
最近开发小程序项目用到了轮播图,默认的有点单调,作为后端程序员,研究一番最终实现了.本文会从思路,代码详细介绍,相信读过此文后,不管以后在开发中碰到轮播图还是需要自定义修改其他的样式都可以按这个思路解 ...
- SQL数据库操作总结
1. 如何增加(创建)数据库 语法 CREATE DATABASE database_name 2.如何增加(创建)数据表 语法 CREATE TABLE table_name { column_na ...
- React简单教程-3-样式
前言 在上一章 React 简单教程-2-ts 和组件参数 中我们新建的子组件 Displayer 没有样式,显得平平无奇,这一篇我们将给他美化一下. CSS 文件 一般的做法,是在你的组件级目录下新 ...
- 『忘了再学』Shell基础 — 30、sed命令的使用
目录 1.sed命令说明 2.行数据操作 (1)查看文件中的数据 (2)删除文件中的数据 (3)向文件中追加数据 (4)向文件中插入数据 (5)修改文件中的多行数据(删除,追加,插入) (6)替换文件 ...
- php 访问控制可见性 public protected private
对属性或方法的访问控制,是通过在前面添加关键字public(公有),protected(受保护的),private(私有)来实现. 被定义为公有的类成员可以在任何地方被访问. 被定义为受保护的类成员则 ...
