In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))

One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.

Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (1), the number of keys in the tree. Then the next line contains Ndistinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.

Output Specification:

For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.

Finally print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all.

Sample Input 1:

8
98 72 86 60 65 12 23 50

Sample Output 1:

98 86 23
98 86 12
98 72 65
98 72 60 50
Max Heap

Sample Input 2:

8
8 38 25 58 52 82 70 60

Sample Output 2:

8 25 70
8 25 82
8 38 52
8 38 58 60
Min Heap

Sample Input 3:

8
10 28 15 12 34 9 8 56

Sample Output 3:

10 15 8
10 15 9
10 28 34
10 28 12 56
Not Heap 考察堆的性质,总的来说很简单。
代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#define MAX 1000
#define DMAX 10000
using namespace std;
typedef long long ll;
int n;
int big,small;
int heap[MAX + ],t[MAX + ];
void print(int h) {
for(int i = ;i <= h;i ++) {
printf("%d",t[i]);
putchar(i < h ? ' ' : '\n');
}
}
void traversal(int k,int h) {
if(k > n) {
return ;
}
t[h] = heap[k];
if(k * > n) print(h);
if(h) {
if(t[h] > t[h - ]) small = ;
else if(t[h] < t[h - ]) big = ;
}
traversal(k * + ,h + );
traversal(k * ,h + );
}
int main() {
scanf("%d",&n);
for(int i = ;i <= n;i ++) {
scanf("%d",&heap[i]);
}
traversal(,);
if(big == small) puts("Not Heap");
else if(big) puts("Max Heap");
else puts("Min Heap");
}
 

pat甲级 1155 Heap Paths (30 分)的更多相关文章

  1. PAT甲级 1155 Heap Paths (30分) 堆模拟

    题意分析: 给出一个1000以内的整数N,以及N个整数,并且这N个数是按照完全二叉树的层序遍历输出的序列,输出所有的整条的先序遍历的序列(根 右 左),以及判断整棵树是否是符合堆排序的规则(判断是大顶 ...

  2. PAT Advanced 1155 Heap Paths (30 分)

    In computer science, a heap is a specialized tree-based data structure that satisfies the heap prope ...

  3. PAT 甲级 1155 Heap Paths

    https://pintia.cn/problem-sets/994805342720868352/problems/1071785408849047552 In computer science, ...

  4. PAT Advanced 1155 Heap Paths (30) [DFS, 深搜回溯,堆]

    题目 In computer science, a heap is a specialized tree-based data structure that satisfies the heap pr ...

  5. PAT 甲级 1080 Graduate Admission (30 分) (简单,结构体排序模拟)

    1080 Graduate Admission (30 分)   It is said that in 2011, there are about 100 graduate schools ready ...

  6. PAT 甲级 1072 Gas Station (30 分)(dijstra)

    1072 Gas Station (30 分)   A gas station has to be built at such a location that the minimum distance ...

  7. PAT 甲级 1049 Counting Ones (30 分)(找规律,较难,想到了一点但没有深入考虑嫌麻烦)***

    1049 Counting Ones (30 分)   The task is simple: given any positive integer N, you are supposed to co ...

  8. PAT 甲级 1030 Travel Plan (30 分)(dijstra,较简单,但要注意是从0到n-1)

    1030 Travel Plan (30 分)   A traveler's map gives the distances between cities along the highways, to ...

  9. PAT 甲级 1026 Table Tennis (30 分)(坑点很多,逻辑较复杂,做了1天)

    1026 Table Tennis (30 分)   A table tennis club has N tables available to the public. The tables are ...

随机推荐

  1. codeforces242E XOR on Segment

    本文版权归ljh2000和博客园共有,欢迎转载,但须保留此声明,并给出原文链接,谢谢合作. 本文作者:ljh2000 作者博客:http://www.cnblogs.com/ljh2000-jump/ ...

  2. django实现图片上传后自动修改尺寸并保存修改后的图到数据库和本地文件系统

    图片上传首先要是设置settings.py文件(与静态文件设置类似) MEDIA_ROOT = os.path.join(BASE_DIR,'media')MEDIA_URL = '/media/' ...

  3. 第四章 SSL和Proxy高级选项

    在前一章,我们已经学习了HTTP消息如何通过Burp Proxy进行拦截和处理,本章我们将继续学习HTTPS协议消息的拦截和处理. HTTPS协议是为了数据传输安全的需要,在HTTP原有的基础上,加入 ...

  4. 【转】通过blktrace, debugfs分析磁盘IO

    前几天微博上有同学问我磁盘util达到了100%时程序性能下降的问题,由于信息实在有限,我也没有办法帮太大的忙,这篇blog只是想给他列一下在磁盘util很高的时候如何通过blktrace+debug ...

  5. 安装Linux环境

    虚拟机:虚拟机(Virtual Machine),在计算机科学中的体系结构里,是指一种特殊的软件,他可以在计算机平台和终端用户之间建立一种环境,而终端用户则是基于这个软件所建立的环境来操作软件.在计算 ...

  6. ASP.NET MVC 路由系统类

    RouteData public class RouteData { private RouteValueDictionary _dataTokens; private IRouteHandler _ ...

  7. 内存保护机制及绕过方法——通过伪造SEHOP链绕过SEHOP保护机制

    1.1    SEHOP保护机制 1.1.1    SEHOP工作原理: SEHOP保护机制的核心就是检查SEH链的完整性,其验证代码如下: BOOL RtlIsValidHandler(handle ...

  8. LeetCode OJ : Different Ways to Add Parentheses(在不同位置增加括号的方法)

    Given a string of numbers and operators, return all possible results from computing all the differen ...

  9. 在.NET Core中连接使用Zookeeper

    一开始找到的是ZookeeperNetEx,但是很多API都很原始,不怎么好用. 最后确定用Rabbit.Zookeeper来做,他对ZookeeperNetEx进行了封装,要简单不少. 和c语言和j ...

  10. keepererrorcode = connectionloss for 错误处理

    自己的环境在虚拟机上,于是使用同事的环境调试问题,发现无法初始化成功,提示keepererrorcode = connectionloss for,于是上网查了下资料整理如下: 1.对比代码中引用的j ...