LeetCode——Edit Distance
Question
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.)
You have the following 3 operations permitted on a word:
a) Insert a character
b) Delete a character
c) Replace a character
Solution
动态规划。参见以前的博客:http://www.cnblogs.com/zhonghuasong/p/6147030.html
Code
class Solution {
public:
int minDistance(string word1, string word2) {
int len1 = word1.length();
int len2 = word2.length();
vector<vector<int>> dp(len1 + 1, vector<int>(len2 + 1, 0));
for (int i = 0; i <= len1; i++)
dp[i][0] = i;
for (int j = 0; j <= len2; j++)
dp[0][j] = j;
for (int i = 1; i <= len1; i++) {
for (int j = 1; j <= len2; j++) {
int tmp = word1[i - 1] == word2[j - 1] ? 0 : 1;
dp[i][j] = min(dp[i - 1][j] + 1, min(dp[i][j - 1] + 1, dp[i - 1][j - 1] + tmp));
}
}
return dp[len1][len2];
}
};
LeetCode——Edit Distance的更多相关文章
- [LeetCode] Edit Distance 编辑距离
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- Leetcode:Edit Distance 解题报告
Edit Distance Given two words word1 and word2, find the minimum number of steps required to convert ...
- [leetcode]Edit Distance @ Python
原题地址:https://oj.leetcode.com/problems/edit-distance/ 题意: Given two words word1 and word2, find the m ...
- [LeetCode] Edit Distance 字符串变换为另一字符串动态规划
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- Leetcode Edit Distance
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- [LeetCode] Edit Distance(很好的DP)
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- LeetCode: Edit Distance && 子序列题集
Title: Given two words word1 and word2, find the minimum number of steps required to convert word1 t ...
- [LeetCode] One Edit Distance 一个编辑距离
Given two strings S and T, determine if they are both one edit distance apart. 这道题是之前那道Edit Distance ...
- Java for LeetCode 072 Edit Distance【HARD】
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
随机推荐
- Apache Kafka源码分析 – ReplicaManager
如果说controller作为master,负责全局的事情,比如选取leader,reassignment等那么ReplicaManager就是worker,负责完成replica的管理工作 主要工作 ...
- d3.js 之SVG:矢量化图形绘制
SVG Scalable Vector Graphics 是一个成熟的W3C标准,被设计用来在web和移动平台 上展示可交互的图形.和HTML类似,SVG也支持CSS和JavaScript.尽管可以使 ...
- Ponds----hdu5438(拓扑排序)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5438 题意:有n个池塘和m个管道:每个池塘的价值是v, 现在由于资金问题要删除池塘:但是删除的池塘 ...
- ubuntu安装mysql步骤
https://dev.mysql.com/downloads/file/?id=477124 ubuntu上安装mysql非常简单只需要几条命令就可以完成. 1. sudo apt-get inst ...
- Flask的配置与路由
配置管理 flask中的配置文件是一个flask.config.Config对象(继承字典),默认配置为: { 'DEBUG': get_de ...
- maven之jre默认配置
需要在用户或者全局settings.xml中做如下配置 例:用户配置: 添加代码: <profile> <id>jdk-1.8</id> <activatio ...
- centos删除乱码名称的文件
常规方法rm已经木有办法删除该文件了. 原理: 当文件名为乱码的时候,无法通过键盘输入文件名,所以在终端下就不能直接利用rm,mv等命令管理文件了.但是每个文件都有一个i节点号,可以通过i节点号来管理 ...
- MySQL整理(三)
一.简单单表操作 (1)简单CRUD 插入查询结果 insert into table1(id,name,age) select id,name,age from table2 where id ...
- MongoDB主从复制+集群
一.读写分离的概念 读写分离,基本的原理是让主数据库处理事务性增.改.删操作(INSERT.UPDATE.DELETE),而从数据库处理SELECT查询操作.数据库复制被用来把事务性操作导致的变更同步 ...
- vultr服务器上搭建PHP运行环境-centos7
安装nginx: yum install nginx 开启Nginx systemctl start nginx 访问你的域名或者ip 例如:quantaedu.com 安装PHP 查看系统版本lsb ...