LeetCode——Edit Distance
Question
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.)
You have the following 3 operations permitted on a word:
a) Insert a character
b) Delete a character
c) Replace a character
Solution
动态规划。参见以前的博客:http://www.cnblogs.com/zhonghuasong/p/6147030.html
Code
class Solution {
public:
int minDistance(string word1, string word2) {
int len1 = word1.length();
int len2 = word2.length();
vector<vector<int>> dp(len1 + 1, vector<int>(len2 + 1, 0));
for (int i = 0; i <= len1; i++)
dp[i][0] = i;
for (int j = 0; j <= len2; j++)
dp[0][j] = j;
for (int i = 1; i <= len1; i++) {
for (int j = 1; j <= len2; j++) {
int tmp = word1[i - 1] == word2[j - 1] ? 0 : 1;
dp[i][j] = min(dp[i - 1][j] + 1, min(dp[i][j - 1] + 1, dp[i - 1][j - 1] + tmp));
}
}
return dp[len1][len2];
}
};
LeetCode——Edit Distance的更多相关文章
- [LeetCode] Edit Distance 编辑距离
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- Leetcode:Edit Distance 解题报告
Edit Distance Given two words word1 and word2, find the minimum number of steps required to convert ...
- [leetcode]Edit Distance @ Python
原题地址:https://oj.leetcode.com/problems/edit-distance/ 题意: Given two words word1 and word2, find the m ...
- [LeetCode] Edit Distance 字符串变换为另一字符串动态规划
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- Leetcode Edit Distance
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- [LeetCode] Edit Distance(很好的DP)
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
- LeetCode: Edit Distance && 子序列题集
Title: Given two words word1 and word2, find the minimum number of steps required to convert word1 t ...
- [LeetCode] One Edit Distance 一个编辑距离
Given two strings S and T, determine if they are both one edit distance apart. 这道题是之前那道Edit Distance ...
- Java for LeetCode 072 Edit Distance【HARD】
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2 ...
随机推荐
- swift中类与结构体
写了12个Person来复习,不过完成同样的代码需要敲键盘的次数相比OC确实少了很多,这很多应该归功于Swift中不写分号,以及少了OC中的中括号. 一.类与结构体 两者在Swift中差不了多少了 类 ...
- JSONP使用
一.什么是JSONP jsonp是一种规则,它是利用创建html的script快的方式,将远端url放到src属性中,并以函数的形式执行远程返回值中的函数. jsonp的出现是为了解决浏览器同源策略的 ...
- 内核通信之Netlink源码分析-用户内核通信原理2
2017-07-05 上文以一个简单的案例描述了通过Netlink进行用户.内核通信的流程,本节针对流程中的各个要点进行深入分析 sock的创建 sock管理结构 sendmsg源码分析 sock的 ...
- 联想yoga table2 1371f 进入bios 的巧妙方法
win8.1 的平板,无键盘,触屏失灵,接了个鼠标 我在这里向大家介绍最后一个方法<ignore_js_op>▲在metro界面下找到设置选项 <ignore_js_op> ...
- mysql5.7新特性探究
一.MySql5.7增加的特性 1.MySql服务方面新特性 1) 初始化方式改变 MySql5.7之前版本初始化方式: scripts/mysql_install_db MySql5.7版本初始化方 ...
- Jenkins+Ant+Jmeter自动化测试平台
持续集成 持续集成是一种软件开发实践,即团队开发成员经常集成他们的工作,通常每个成员每天至少集成一次,也就意味着每天可能会发生多次集成.每次集成都通过自动化的构建(包括编译,发布,自动 ...
- PAT 1151 LCA in a Binary Tree[难][二叉树]
1151 LCA in a Binary Tree (30 分) The lowest common ancestor (LCA) of two nodes U and V in a tree is ...
- HTML5游戏开发系列教程7(译)
原文地址:http://www.script-tutorials.com/html5-game-development-lesson-7/ 今天我们将完成我们第一个完整的游戏--打砖块.这次教程中,将 ...
- MyBatisPartA
(正在补充) 1.从第一个程序开始,通过mybatis实现数据库表内容的增删改查 (源码zip包) 1.0准备工作 建数据库mybatis,在其中创建表sql语句如下: ; -- ---------- ...
- Error: registers may not be the same -- `strexb r3,r2,[r3]'
tmp\ccFziEge.s:914: Error: registers may not be the same -- `strexb r3,r2,[r3]'tmp\ccFziEge.s:968: E ...