Easier Done Than Said?
FnordCom is developing such a password generator. You work in
the quality control department, and it's your job to test the generator and make
sure that the passwords are acceptable. To be acceptable, a password must
satisfy these three rules:
It must contain at least one vowel.
It
cannot contain three consecutive vowels or three consecutive
consonants.
It cannot contain two consecutive occurrences of the same
letter, except for 'ee' or 'oo'.
(For the purposes of this problem, the
vowels are 'a', 'e', 'i', 'o', and 'u'; all other letters are consonants.) Note
that these rules are not perfect; there are many common/pronounceable words that
are not acceptable.
one per line, followed by a line containing only the word 'end' that signals the
end of the file. Each password is at least one and at most twenty letters long
and consists only of lowercase letters.
acceptable, using the precise format shown in the example.
#include <stdio.h>
#include <string.h> int main(){
char s[];
int length;
int i;
int flag1;
int flag2;
int flag3;
char compareString[]="aeiou"; while(){
scanf("%s",s); if(strcmp(s,"end")==)
break; length=strlen(s);
flag1=;
flag2=;
flag3=; for(i=;i<length;i++){
if(s[i]=='a' || s[i]=='e' || s[i]=='i' || s[i]=='o' || s[i]=='u')
flag1=;
} if(flag1==){
printf("<%s> is not acceptable.\n",s);
continue;
} for(i=;i<length-;i++){
if(s[i]==s[i+] && s[i]!='e' && s[i]!='o')
flag2=;
} if(flag2==){
printf("<%s> is not acceptable.\n",s);
continue;
} for(i=;i<length-;i++){
if(strchr(compareString,s[i])!=NULL && strchr(compareString,s[i+])!=NULL && strchr(compareString,s[i+])!=NULL){
flag3=;
break;
} if(strchr(compareString,s[i])==NULL && strchr(compareString,s[i+])==NULL && strchr(compareString,s[i+])==NULL){
flag3=;
break;
} } if(flag3==){
printf("<%s> is not acceptable.\n",s);
continue;
} printf("<%s> is acceptable.\n",s); }
return ;
}
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