Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u

Submit Status

Description

One day, at the "Russian Code Cup" event it was decided to play football as an out of competition event. All participants was divided into nteams and played several matches, two teams could not play against each other more than once.

The appointed Judge was the most experienced member — Pavel. But since he was the wisest of all, he soon got bored of the game and fell asleep. Waking up, he discovered that the tournament is over and the teams want to know the results of all the matches.

Pavel didn't want anyone to discover about him sleeping and not keeping an eye on the results, so he decided to recover the results of all games. To do this, he asked all the teams and learned that the real winner was friendship, that is, each team beat the other teams exactly ktimes. Help Pavel come up with chronology of the tournir that meets all the conditions, or otherwise report that there is no such table.

Input

The first line contains two integers — n and k (1 ≤ n, k ≤ 1000).

Output

In the first line print an integer m — number of the played games. The following m lines should contain the information about all the matches, one match per line. The i-th line should contain two integers ai and bi (1 ≤ ai, bi ≤ nai ≠ bi). The numbers ai and bi mean, that in the i-th match the team with number ai won against the team with number bi. You can assume, that the teams are numbered from 1 ton.

If a tournir that meets the conditions of the problem does not exist, then print -1.

Sample Input

Input
3 1
Output
3
1 2
2 3
3 1

Source

很久之前做的题,输出所有的情况就行了。
#include <iostream>
#include <stdio.h>
typedef long long LL;
using namespace std;
int main()
{
int i,n,m,k,j;
cin>>n>>k;
if (n-<*k)
cout<<-<<endl;
else
{
cout<<n*k<<endl;
for (i=;i<=n;i++)
{
for (j=;j<k;j++)
printf("%d %d\n",i,(i+j)%n+);
}
}
return ;
}

Codeforces 417 C的更多相关文章

  1. Codeforces 417 D. Cunning Gena

    按monitor排序,然后状压DP... . D. Cunning Gena time limit per test 1 second memory limit per test 256 megaby ...

  2. Codeforces Round #417 (Div. 2) D. Sagheer and Kindergarten(树中判祖先)

    http://codeforces.com/contest/812/problem/D 题意: 现在有n个孩子,m个玩具,每次输入x y,表示x孩子想要y玩具,如果y玩具没人玩,那么x就可以去玩,如果 ...

  3. Codeforces Round #417 (Div. 2) B. Sagheer, the Hausmeister

    http://codeforces.com/contest/812/problem/B 题意: 有n层楼,每层楼有m个房间,1表示灯开着,0表示灯关了.最两侧的是楼梯. 现在每从一个房间移动到另一个房 ...

  4. Codeforces Round #417 (Div. 2) B. Sagheer, the Hausmeister —— DP

    题目链接:http://codeforces.com/problemset/problem/812/B B. Sagheer, the Hausmeister time limit per test ...

  5. [Codeforces Round#417 Div.2]

    来自FallDream的博客,未经允许,请勿转载,谢谢. 有毒的一场div2 找了个1300的小号,结果B题题目看错没交  D题题目剧毒 E题差了10秒钟没交上去. 233 ------- A.Sag ...

  6. Codeforces Round #417 (Div. 2)-A. Sagheer and Crossroad

    [题意概述] 在一个十字路口 ,给定红绿灯的情况, 按逆时针方向一次给出各个路口的左转,直行,右转,以及行人车道,判断汽车是否有可能撞到行人 [题目分析] 需要在逻辑上清晰,只需要把所有情况列出来即可 ...

  7. Codeforces Round #417 (Div. 2) C. Sagheer and Nubian Market

    time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standa ...

  8. Codeforces Round #417 C. Sagheer and Nubian Market

    C. Sagheer and Nubian Market time limit per test  2 seconds memory limit per test  256 megabytes   O ...

  9. Codeforces Round #417 B. Sagheer, the Hausmeister

    B. Sagheer, the Hausmeister time limit per test  1 second memory limit per test  256 megabytes   Som ...

随机推荐

  1. 蝙蝠算法-python实现

    BAIndividual.py import numpy as np import ObjFunction class BAIndividual: ''' individual of bat algo ...

  2. javaScript基础练习题-下拉框制作

    1.基础回顾 如何让一个段javascript在文档加载后执行,(因为自己忘了,所以顺便复习一下) window.onload = function(){}; <!DOCTYPE html PU ...

  3. 解决:Angular-cli:执行ng-build --prod后,dist文件里无js文件、文件未压缩等问题

    Angular2.0于2016年9月上线,我于9月入坑. 入坑以来,一直让我很困惑的问题 1.angular-cli是个什么鬼东西? 2.为什么我们自己的资源文件还没写什么,就有起码50多个js文件加 ...

  4. Dedecms include\dialog\select_soft_post.php Upload Any Files To The Specified Directory Via Variable Not Initial Flaw Bypass Extension Defence

    目录 . 漏洞描述 . 漏洞触发条件 . 漏洞影响范围 . 漏洞代码分析 . 防御方法 . 攻防思考 1. 漏洞描述 综合来说,这个漏洞的根源是"register_globals = on& ...

  5. java导出txt文本

    页面 项目结构 html代码 <html> </head> <body> <form action="down/downLoad" met ...

  6. HDU2196computer(树上最远距离 + DP)

    Computer Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Su ...

  7. --Dirring love 音乐(01背包问题)

    解题思路: dp[i][j] 前 i 首歌放入 j 容量中的最大热情度. 前 i 首歌 放到 j 容量中 dp[i][j]= dp[i-1][j-m[i]]+r[i]   (注意:如果 j 容量 &l ...

  8. Yii2 如何使用事件

    原文地址:http://www.fancyecommerce.com/2016/04/29/yii2-%E4%BD%BF%E7%94%A8event-1-%EF%BC%8C%E5%A6%82%E4%B ...

  9. [asp.net mvc]自定义filter

    写在前面 最近在摸索mvc,在app中的webview中嵌入h5应用,经常需要用到对cookie的读取操作.所以想到通过自定义的filter截取cookie,然后通过在action上面打特性的方式针对 ...

  10. IHttpModule在webconfig中的注册

    在asp.net中,提供了两种方式用来解决获取由asp.net服务器创建和维护的HttpApplication对象,方便注册HttpApplication对象的事件处理.这两种方式为:IHtpModu ...