【HDU 3966】Aragorn's Story（未完待续）

我无限Runtime Error(ACCESS_VIOLATION)。不知道怎么搞得/(ㄒoㄒ)/~~

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#define for1(i,a,n) for(int i=(a);i<=(n);++i)
#define for2(i,a,n) for(int i=(a);i<(n);++i)
#define for3(i,a,n) for(int i=(a);i>=(n);--i)
#define for4(i,a,n) for(int i=(a);i>(n);--i)
#define CC(i,a) memset(i,a,sizeof(i));
using namespace std;
const int MAX=50010;
inline const int max(const int &a,const int &b){return a>b?a:b;}
inline const int min(const int &a,const int &b){return a<b?a:b;}
inline void swapp(int &a,int &b){int c=a;a=b;b=c;}
struct node{int to,nxt;}E[MAX<<1];
int N,point[MAX],cnt,sum[MAX<<2],up[MAX],lazy[MAX<<2],size[MAX],son[MAX],fa[MAX],tot,which[MAX],pos[MAX],deep[MAX],w[MAX];
inline void init(){CC(point,0);CC(deep,0);CC(sum,0);CC(up,0);CC(lazy,0);CC(size,0);CC(son,0);CC(fa,0);CC(which,0);CC(pos,0);CC(deep,0);CC(w,0);cnt=0;tot=0;}
inline void insect(int x,int y){E[++cnt].nxt=point[x];E[cnt].to=y;point[x]=cnt;}
inline void dfs1(int x){
    int nmax=0,num=0;
    size[x]=1;
    for(int tmp=point[x];tmp;tmp=E[tmp].nxt)if(E[tmp].to!=fa[x]){
        fa[E[tmp].to]=x;
        deep[E[tmp].to]=deep[x]+1;
        dfs1(E[tmp].to);
        size[x]+=size[E[tmp].to];
        if (size[E[tmp].to]>nmax){nmax=size[E[tmp].to];num=E[tmp].to;}
    }son[x]=num;
}
inline void dfs2(int x){
    pos[x]=++tot;which[tot]=x;
    if (!son[x]) return;
    up[son[x]]=up[x];
    dfs2(son[x]);
    for(int tmp=point[x];tmp;tmp=E[tmp].nxt)if((E[tmp].to!=fa[x])&&(E[tmp].to!=son[x])){
        up[E[tmp].to]=E[tmp].to;
        dfs2(E[tmp].to);
    }
}
inline void pushup(int rt){sum[rt]=sum[rt<<1]+sum[rt<<1|1];}
inline void pushdown(int ln,int rn,int rt){
    if (lazy[rt]!=0){
        lazy[rt<<1]+=lazy[rt];
        lazy[rt<<1|1]+=lazy[rt];
        sum[rt<<1]+=ln*lazy[rt];
        sum[rt<<1|1]+=rn*lazy[rt];
        lazy[rt]=0;
    }
}
inline void buildtree(int l,int r,int rt){
    if (l==r){sum[rt]=w[which[l]];return;}
    int mid=(l+r)>>1;
    buildtree(l,mid,rt<<1);
    buildtree(mid+1,r,rt<<1|1);
    pushup(rt);
}
inline void addtree(int L,int R,int ad,int l,int r,int rt){
    if ((L<=l)&&(r<=R)){lazy[rt]+=ad;sum[rt]+=ad*(r-l+1);return;}
    int mid=(l+r)>>1;
    pushdown(mid-l+1,r-mid,rt);
    if (L<=mid) addtree(L,R,ad,l,mid,rt<<1);
    if (R>mid) addtree(L,R,ad,mid+1,r,rt<<1|1);
    pushup(rt);
}
inline void addd(int x,int y,int k){
    while (up[x]!=up[y]){
        if (deep[up[x]]<deep[up[y]])swapp(x,y);
        addtree(pos[up[x]],pos[x],k,1,N,1);
        x=fa[up[x]];
    }if (deep[x]>deep[y])swapp(x,y);
    addtree(pos[x],pos[y],k,1,N,1);
}
inline void query(int po,int l,int r,int rt){
    if (l==r){printf("%d\n",sum[rt]);return;}
    int mid=(l+r)>>1;
    pushdown(mid-l+1,r-mid,rt);
    if (po<=mid) query(po,l,mid,rt<<1);
    else query(po,mid+1,r,rt<<1|1);
}
int main(){
    int M,Q,x,y,c1,c2,k; char c;
    while (~scanf("%d%d%d\n",&N,&M,&Q)){
        init();
        for1(i,1,N)scanf("%d",&w[i]);
        for1(i,1,M){
            scanf("%d%d\n",&x,&y);
            insect(x,y);insect(y,x);
        }deep[1]=1;
        dfs1(1);
        up[1]=1;
        dfs2(1);
        buildtree(1,N,1);
        while(Q--){
            c=getchar();
            switch(c){
                case 'I':
                    scanf("%d%d%d\n",&c1,&c2,&k);
                    addd(c1,c2,k);
                break;
                case 'D':
                    scanf("%d%d%d\n",&c1,&c2,&k);
                    addd(c1,c2,k*(-1));
                break;
                case 'Q':
                    scanf("%d\n",&k);
                    query(which[k],1,N,1);
                break;
            }
        }
    }return 0;
}

等省选完再看为什么RE吧，现在还有很多东西要学，在此存一下代码。