[刷题] 235 Lowest Common Ancestor of a Binary Search Tree
要求
- 给定一棵二分搜索树和两个节点,寻找这两个节点的最近公共祖先
示例
- 2和8的最近公共祖先是6
- 2和4的最近公共祖先是2

思路
- p q<node
- node<p q
- p<=node<=q
实现
1 class Solution {
2 public:
3 TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
4
5 assert( p != NULL && q != NULL );
6
7 if( root == NULL )
8 return NULL;
9
10 if( p->val < root->val && q->val < root->val )
11 return lowestCommanAncestor( root->left , p , q );
12 if( p->val > root->val && q->val > root->val )
13 return lowestCommanAncestor( root->right , p , q );
14
15 return root;
16 }
17 };
相关
- 98 Validate Binary Search Tree
- 450 Delete Node in a BST
- 108 Convert Sorted Array to Binary Search Tree
- 230 Kth Smallest Element in a BST
- 236 Lowest Common Ancestor of a Binary Tree
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