Given a set of distinct integers, S, return all possible subsets.

Note:

  • Elements in a subset must be in non-descending order.
  • The solution set must not contain duplicate subsets.

题目要求 :

求整数数组的所有子集

注意:

1、子集元素按非降序排列

2、不包含重复的子集

解题思路:

求解这类诸如子集的题目,都可以采用回溯法。(剪枝+递归)

代码如下:

class Solution {
private:
vector<vector<int> > ans;
public:
void collectSubSet(vector<int> &S,vector<int> x,int len,int idx){
if(idx==len){
vector<int> subset;
for(int i=;i<len;i++){
if(x[i]!=)
subset.push_back(S[i]);
}
sort(subset.begin(),subset.end(),less<int>());
ans.push_back(subset);
return;
}
x[idx]=;
collectSubSet(S,x,len,idx+);
x[idx]=;
collectSubSet(S,x,len,idx+);
} vector<vector<int> > subsets(vector<int> &S) {
int len=S.size();
vector<int> x(len);
// sort(S.begin(),S.end(),greater<int>());
collectSubSet(S,x,len,);
// sort(ans.begin(),ans.end(),cmp());
return ans;
}
};

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