题目

Implement wildcard pattern matching with support for '?' and '*'.

'?' Matches any single character.
'*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). The function prototype should be:
bool isMatch(const char *s, const char *p) Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "*") → true
isMatch("aa", "a*") → true
isMatch("ab", "?*") → true
isMatch("aab", "c*a*b") → false 题解
本文代码引用自:http://blog.csdn.net/perfect8886/article/details/22689147
 1     public boolean isMatch(String s, String p) {  
 2         int i = 0;  
 3         int j = 0;  
 4         int star = -1;  
 5         int mark = -1;  
 6         while (i < s.length()) {  
 7             if (j < p.length()  
 8                     && (p.charAt(j) == '?' || p.charAt(j) == s.charAt(i))) {  
 9                 ++i;  
                 ++j;  
             } else if (j < p.length() && p.charAt(j) == '*') {  
                 star = j++;  
                 mark = i;  
             } else if (star != -1) {  
                 j = star + 1;  
                 i = ++mark;  
             } else {  
                 return false;  
             }  
         }  
         while (j < p.length() && p.charAt(j) == '*') {  
             ++j;  
         }  
         return j == p.length();  
     }
 

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