PAT 甲级 1083 List Grades (25 分)
1083 List Grades (25 分)
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification:
Each input file contains one test case. Each case is given in the following format:
N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.
Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
Sample Output 2:
NONE
#include<iostream>
#include<set>
#include<string> using namespace std; struct student
{
string name;
string ID;
int grade; bool operator<(const student stu) const
{
if(grade < stu.grade)
return true;
else
return false;
} bool operator>(const student stu) const
{
if(grade > stu.grade)
return true;
else
return false;
}
}; int main()
{
int N ,flag = ,grade1,grade2;
student stu;
set<student> s; cin>>N; for(int i=;i<N;++i)
{
cin>>stu.name>> stu.ID>>stu.grade; s.insert(stu);
} cin>>grade1>>grade2; set<student>::reverse_iterator begin = s.rbegin(),end = s.rend(),i; for(i=begin;i!=end;++i)
{
if((*i).grade >= grade1 && (*i).grade <= grade2)
{
cout<<i->name<<" "<<i->ID<<endl;
flag = ;
}
} if(flag)
cout<<"NONE"<<endl;
}
PAT 甲级 1083 List Grades (25 分)的更多相关文章
- PAT 甲级 1028 List Sorting (25 分)(排序,简单题)
1028 List Sorting (25 分) Excel can sort records according to any column. Now you are supposed to i ...
- PAT 甲级 1020 Tree Traversals (25分)(后序中序链表建树,求层序)***重点复习
1020 Tree Traversals (25分) Suppose that all the keys in a binary tree are distinct positive intege ...
- PAT 甲级 1146 Topological Order (25 分)(拓扑较简单,保存入度数和出度的节点即可)
1146 Topological Order (25 分) This is a problem given in the Graduate Entrance Exam in 2018: Which ...
- PAT 甲级 1071 Speech Patterns (25 分)(map)
1071 Speech Patterns (25 分) People often have a preference among synonyms of the same word. For ex ...
- PAT 甲级 1063 Set Similarity (25 分) (新学,set的使用,printf 输出%,要%%)
1063 Set Similarity (25 分) Given two sets of integers, the similarity of the sets is defined to be ...
- PAT 甲级 1059 Prime Factors (25 分) ((新学)快速质因数分解,注意1=1)
1059 Prime Factors (25 分) Given any positive integer N, you are supposed to find all of its prime ...
- PAT 甲级 1051 Pop Sequence (25 分)(模拟栈,较简单)
1051 Pop Sequence (25 分) Given a stack which can keep M numbers at most. Push N numbers in the ord ...
- PAT 甲级 1048 Find Coins (25 分)(较简单,开个数组记录一下即可)
1048 Find Coins (25 分) Eva loves to collect coins from all over the universe, including some other ...
- PAT 甲级 1037 Magic Coupon (25 分) (较简单,贪心)
1037 Magic Coupon (25 分) The magic shop in Mars is offering some magic coupons. Each coupon has an ...
随机推荐
- spring整合junit报错
1.Could not autowire field: private javax.servlet.http.HttpServletRequest 参考:https://www.cnblogs.com ...
- vue中动态加载组件+开发者模式+JS参数值传递和引用传递
今天写vue里面通过接口反参动态加载组件时候 跟着同学...学习到了 一.先说说vue 内置组件 component 的用法 component组件可以来专门用来进行组件的切换,使用is来绑定你的组件 ...
- 在线自动创建springboot工程
https://start.spring.io/
- leetcode-algorithms 目录
leetcode算法目录 题号 链接 难度等级 36 leetcode-algorithms-36 Valid Sudoku medium 35 leetcode-algorithms-35 Sear ...
- webstorm keys
{"licenseId":"ThisCrackLicenseId","licenseeName":"xuza",&quo ...
- 网站文档模式总是以Quirks文档模式解析网站
<meta name="renderer" content="webkit"/> <meta http-equiv="X-UA-Co ...
- 剑指Offer 37. 数字在排序数组中出现的次数 (数组)
题目描述 统计一个数字在排序数组中出现的次数. 题目地址 https://www.nowcoder.com/practice/70610bf967994b22bb1c26f9ae901fa2?tpId ...
- JAVA将汉字转换为全拼以及返回中文的首字母,将字符串转移为ASCII码
import net.sourceforge.pinyin4j.PinyinHelper;import net.sourceforge.pinyin4j.format.HanyuPinyinCaseT ...
- linux ar命令参数及用法详解--linux建立、修改或抽取备存文件命
功能说明:建立或修改备存文件,或是从备存文件中抽取文件. 语 法:ar[-dmpqrtx][cfosSuvV][a<成员文件>][b<成员文件>][i<成员文件>] ...
- Mac + PyCharm 安装 Opencv3 + python2.7
本文地址:http://www.cnblogs.com/QingHuan/p/7354074.html 转载请注明本文地址,方便读者查看本文更新,谢谢! 今天要在Mac上安装OpenCV,过程非常曲折 ...