PAT 甲级 1083 List Grades (25 分)
1083 List Grades (25 分)
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification:
Each input file contains one test case. Each case is given in the following format:
N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.
Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
Sample Output 2:
NONE
#include<iostream>
#include<set>
#include<string> using namespace std; struct student
{
string name;
string ID;
int grade; bool operator<(const student stu) const
{
if(grade < stu.grade)
return true;
else
return false;
} bool operator>(const student stu) const
{
if(grade > stu.grade)
return true;
else
return false;
}
}; int main()
{
int N ,flag = ,grade1,grade2;
student stu;
set<student> s; cin>>N; for(int i=;i<N;++i)
{
cin>>stu.name>> stu.ID>>stu.grade; s.insert(stu);
} cin>>grade1>>grade2; set<student>::reverse_iterator begin = s.rbegin(),end = s.rend(),i; for(i=begin;i!=end;++i)
{
if((*i).grade >= grade1 && (*i).grade <= grade2)
{
cout<<i->name<<" "<<i->ID<<endl;
flag = ;
}
} if(flag)
cout<<"NONE"<<endl;
}
PAT 甲级 1083 List Grades (25 分)的更多相关文章
- PAT 甲级 1028 List Sorting (25 分)(排序,简单题)
1028 List Sorting (25 分) Excel can sort records according to any column. Now you are supposed to i ...
- PAT 甲级 1020 Tree Traversals (25分)(后序中序链表建树,求层序)***重点复习
1020 Tree Traversals (25分) Suppose that all the keys in a binary tree are distinct positive intege ...
- PAT 甲级 1146 Topological Order (25 分)(拓扑较简单,保存入度数和出度的节点即可)
1146 Topological Order (25 分) This is a problem given in the Graduate Entrance Exam in 2018: Which ...
- PAT 甲级 1071 Speech Patterns (25 分)(map)
1071 Speech Patterns (25 分) People often have a preference among synonyms of the same word. For ex ...
- PAT 甲级 1063 Set Similarity (25 分) (新学,set的使用,printf 输出%,要%%)
1063 Set Similarity (25 分) Given two sets of integers, the similarity of the sets is defined to be ...
- PAT 甲级 1059 Prime Factors (25 分) ((新学)快速质因数分解,注意1=1)
1059 Prime Factors (25 分) Given any positive integer N, you are supposed to find all of its prime ...
- PAT 甲级 1051 Pop Sequence (25 分)(模拟栈,较简单)
1051 Pop Sequence (25 分) Given a stack which can keep M numbers at most. Push N numbers in the ord ...
- PAT 甲级 1048 Find Coins (25 分)(较简单,开个数组记录一下即可)
1048 Find Coins (25 分) Eva loves to collect coins from all over the universe, including some other ...
- PAT 甲级 1037 Magic Coupon (25 分) (较简单,贪心)
1037 Magic Coupon (25 分) The magic shop in Mars is offering some magic coupons. Each coupon has an ...
随机推荐
- vs 设置自动缩进tab转换成空格
工具 选项 文本编辑器 如下图 选中插入空格 使用技巧: 按Ctrl+K+F组合键,可以自动进行代码对齐.
- css颜色的五种表示方法
一.最简单.最古老的颜色类型在CSS颜色的关键词,如red blue等. 二.十六进制值,如#0000. 三.RGB: rgb(255,0,0),这是给定的三个参数表示的红色,绿色和蓝色通道的颜色值每 ...
- 关于规范NOIP试题管理办法的通知
由CCF主办的NOIP赛事举行在即,保密起见,现将有关规定发给各省赛区组织单位. 1.NOI各省组织单位负责试题保密工作. 2.NOIP初赛试卷为纸质版,复赛试卷为电子版. 3.在初赛进行中,如有选手 ...
- C#mvc下拉框绑定
控制器 ViewData["select1"] = new SelectList(b.bd(),"names","names"); 视图 @ ...
- php解析Excel表格并且导入MySQL数据库
最近根据客户需求,需要增加一个导入Excel表格的功能,Excel中存放的是知识库中医知识的分类体系目录.是在thinkphp框架下编写的代码,用的是phpexcel第三方包.测试环境用的是xampp ...
- 移动端H5拍照代码实现及外网部署
最近的工作中,遇到了一个需求:对于无APP登陆权限的人员,提供拍照上传功能,以便生成更完善的出工记录.经研究讨论,决定实现的机制为:由合法的人员登陆APP认领相关工作任务,并生成当天当工作的唯一二维码 ...
- JAVA8之Lambda表达式与方法引用表达式
一.Lambda表达式 基本语法: lambdaParameters->lambdaBody lambdaParameters传递参数,lambdaBody用于编写逻辑,lambda表达式会生成 ...
- Postman插件使用
Postman插件:模拟前端请求后台,用于后台对外接口测试 POSTMAN解决..先解压Postman_v4.1.3.rar 然后按自己实际解压的文件夹里面的这个文件夹_metadata前面的_去掉 ...
- CMD命令,动态执行存储或DML命令
--exec master..xp_cmdshell CMD命令 --EXECUTE sys.sp_sqlexec 执行存储 --EXEC sp_executesql 执行DML语句
- 2017-2018 ACM-ICPC NEERC B题Berland Army 拓扑排序+非常伤脑筋的要求
题目链接:http://codeforces.com/contest/883/problem/B There are n military men in the Berland army. Some ...