Educational Codeforces Round 33 (Rated for Div. 2) D. Credit Card
2 seconds
256 megabytes
standard input
standard output
Recenlty Luba got a credit card and started to use it. Let's consider n consecutive days Luba uses the card.
She starts with 0 money on her account.
In the evening of i-th day a transaction ai occurs. If ai > 0, then ai bourles are deposited to Luba's account. If ai < 0, then ai bourles are withdrawn. And if ai = 0, then the amount of money on Luba's account is checked.
In the morning of any of n days Luba can go to the bank and deposit any positive integer amount of burles to her account. But there is a limitation: the amount of money on the account can never exceed d.
It can happen that the amount of money goes greater than d by some transaction in the evening. In this case answer will be «-1».
Luba must not exceed this limit, and also she wants that every day her account is checked (the days when ai = 0) the amount of money on her account is non-negative. It takes a lot of time to go to the bank, so Luba wants to know the minimum number of days she needs to deposit some money to her account (if it is possible to meet all the requirements). Help her!
The first line contains two integers n, d (1 ≤ n ≤ 105, 1 ≤ d ≤ 109) —the number of days and the money limitation.
The second line contains n integer numbers a1, a2, ... an ( - 104 ≤ ai ≤ 104), where ai represents the transaction in i-th day.
Print -1 if Luba cannot deposit the money to her account in such a way that the requirements are met. Otherwise print the minimum number of days Luba has to deposit money.
5 10
-1 5 0 -5 3
0
3 4
-10 0 20
-1
5 10
-5 0 10 -11 0
2
【题意】:白天存钱,晚上加减,一旦见零,马上非负。钱有上限,最少几存。
【分析】:
【代码】:
Educational Codeforces Round 33 (Rated for Div. 2) D. Credit Card的更多相关文章
- Educational Codeforces Round 33 (Rated for Div. 2) E. Counting Arrays
题目链接 题意:给你两个数x,yx,yx,y,让你构造一些长为yyy的数列,让这个数列的累乘为xxx,输出方案数. 思路:考虑对xxx进行质因数分解,设某个质因子PiP_iPi的的幂为kkk,则这个 ...
- Educational Codeforces Round 33 (Rated for Div. 2) F. Subtree Minimum Query(主席树合并)
题意 给定一棵 \(n\) 个点的带点权树,以 \(1\) 为根, \(m\) 次询问,每次询问给出两个值 \(p, k\) ,求以下值: \(p\) 的子树中距离 \(p \le k\) 的所有点权 ...
- Educational Codeforces Round 33 (Rated for Div. 2) 题解
A.每个状态只有一种后续转移,判断每次转移是否都合法即可. #include <iostream> #include <cstdio> using namespace std; ...
- Educational Codeforces Round 33 (Rated for Div. 2)A-F
总的来说这套题还是很不错的,让我对主席树有了更深的了解 A:水题,模拟即可 #include<bits/stdc++.h> #define fi first #define se seco ...
- Educational Codeforces Round 33 (Rated for Div. 2) C. Rumor【并查集+贪心/维护集合最小值】
C. Rumor time limit per test 2 seconds memory limit per test 256 megabytes input standard input outp ...
- Educational Codeforces Round 33 (Rated for Div. 2) B. Beautiful Divisors【进制思维/打表】
B. Beautiful Divisors time limit per test 2 seconds memory limit per test 256 megabytes input standa ...
- Educational Codeforces Round 33 (Rated for Div. 2) A. Chess For Three【模拟/逻辑推理】
A. Chess For Three time limit per test 1 second memory limit per test 256 megabytes input standard i ...
- Educational Codeforces Round 33 (Rated for Div. 2)
A. Chess For Three time limit per test 1 second memory limit per test 256 megabytes input standard i ...
- Educational Codeforces Round 33 (Rated for Div. 2) D题 【贪心:前缀和+后缀最值好题】
D. Credit Card Recenlty Luba got a credit card and started to use it. Let's consider n consecutive d ...
随机推荐
- 【转载】Linux下安装LoadRunner LoadGenerator
原文地址:[转载]Linux下安装LoadRunner LoadGenerator作者:邱建忠tester LR的负载机安装在linux的理由: 1.windows xp,双核+4G内存,基本上每个v ...
- mybatis批量添加、批量删除
<!-- 批量添加 --> <insert id="insertNameListSynHisBatch" parameterType="java.uti ...
- 【PTA】Tree Traversals Again
题目如下: An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For e ...
- 聊聊、Mybatis Java注解实现
AbstractAnnotationConfigDispatcherServletInitializer public class MvcInitializer extends AbstractAnn ...
- composer 库无法提交git
composer require firebase/php-jwt 安装了该库,想提交到版本库,无论如何也提交不上去,.ignore中也没忽略,网上寻找答案,说有个.git文件夹需要删除 PHPSTO ...
- 【Luogu】P3760异或和(权值树状数组)
题目链接 再次声明以后我见到位运算一定第一时间想把它拆成每一位算 本题就是有个前缀和sum[],然后让你求每一位有多少对i,j满足sum[i]-sum[j]在那一位上是1 考虑怎样才能减出1来 如果s ...
- Web实现数据库链接的登录注册修改密码功能
/** * Copyright (C), 2017-2017 * FileName: User * Author: ichimoku * Date: 2017/12/5 14:31 * version ...
- canvas2D 基础知识 浅析
1.canvas HTML5给出的一个可以展示绘图内容的标签 使用领域: (推荐网站:threejs.org) 1. 游戏 2. 可视化数据 3. Banner广告 4. 多媒体 (1)在 c ...
- Java并发(2)- 聊聊happens-before
引言 上一篇文章聊到了Java内存模型,在其中我们说JMM是建立在happens-before(先行发生)原则之上的. 为什么这么说呢?因为在Java程序的执行过程中,编译器和处理器对我们所写的代码进 ...
- iphone上做webapp时总会识别一串数字为手机号码并变黑显示
iphone上网页里总会识别一串数字为手机号码并变黑显示 只需要在head里加上一个特别的meta即可 <meta name="format-detection" conte ...