Knight Tournament (set)
Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tournament (it was a weekend, after all). Now you are really curious about the results of the tournament. This time the tournament in Berland went as follows:
- There are n knights participating in the tournament. Each knight was assigned his unique number — an integer from 1 to n.
- The tournament consisted of m fights, in the i-th fight the knights that were still in the game with numbers at least li and at most ri have fought for the right to continue taking part in the tournament.
- After the i-th fight among all participants of the fight only one knight won — the knight number xi, he continued participating in the tournament. Other knights left the tournament.
- The winner of the last (the m-th) fight (the knight number xm) became the winner of the tournament.
You fished out all the information about the fights from your friends. Now for each knight you want to know the name of the knight he was conquered by. We think that the knight number b was conquered by the knight number a, if there was a fight with both of these knights present and the winner was the knight number a.
Write the code that calculates for each knight, the name of the knight that beat him.
Input
The first line contains two integers n, m (2 ≤ n ≤ 3·105; 1 ≤ m ≤ 3·105) — the number of knights and the number of fights. Each of the following m lines contains three integers li, ri, xi (1 ≤ li < ri ≤ n; li ≤ xi ≤ ri) — the description of the i-th fight.
It is guaranteed that the input is correct and matches the problem statement. It is guaranteed that at least two knights took part in each battle.
Output
Print n integers. If the i-th knight lost, then the i-th number should equal the number of the knight that beat the knight number i. If the i-th knight is the winner, then the i-th number must equal 0.
题解:用set来模拟
代码:
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<set>
using namespace std;
int a[1000005];
int main()
{
set<int>s;
set<int>::iterator it;
int n,m;
cin>>n>>m;
s.clear();
for(int t=1;t<=n;t++)
{
s.insert(t);
}
int l,r,x;
for (int t=1;t<=m;t++)
{
x=s.size();
scanf("%d%d%d",&l,&r,&x);
it=s.lower_bound(l);
int h;
while (it!=s.end() && *it<=r)
{
h=*it;
it++;
if (h!=x)
{
a[h]=x;
s.erase(h);
}
}
}
printf("%d",a[1]);
for(int t=2;t<=n;t++)
{
printf(" %d",a[t]);
}
return 0;
}
Knight Tournament (set)的更多相关文章
- D - Knight Tournament(set)
Problem description Hooray! Berl II, the king of Berland is making a knight tournament. The king has ...
- CodeForce 356A Knight Tournament(set应用)
Knight Tournament time limit per test 3 seconds memory limit per test 256 megabytes input standard ...
- Codeforces Round #207 (Div. 1) A. Knight Tournament (线段树离线)
题目:http://codeforces.com/problemset/problem/356/A 题意:首先给你n,m,代表有n个人还有m次描述,下面m行,每行l,r,x,代表l到r这个区间都被x所 ...
- CodeForces - 357C Knight Tournament 伪并查集(区间合并)
Knight Tournament Hooray! Berl II, the king of Berland is making a knight tournament. The king has a ...
- Knight Tournament 合并区间
Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the me ...
- codeforces 357C Knight Tournament(set)
Description Hooray! Berl II, the king of Berland is making a knight tournament. The king has already ...
- HDU 1372 Knight Moves (bfs)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1372 Knight Moves Time Limit: 2000/1000 MS (Java/Othe ...
- uva439 - Knight Moves(BFS求最短路)
题意:8*8国际象棋棋盘,求马从起点到终点的最少步数. 编写时犯的错误:1.结构体内没构造.2.bfs函数里返回条件误写成起点.3.主函数里取行标时未注意书中的图. #include<iostr ...
- poj2243 Knight Moves(BFS)
题目链接 http://poj.org/problem?id=2243 题意 输入8*8国际象棋棋盘上的两颗棋子(a~h表示列,1~8表示行),求马从一颗棋子跳到另一颗棋子需要的最短路径. 思路 使用 ...
随机推荐
- What is Photon Server?
http://blog.csdn.net/menuconfig/article/details/8215033 Photon Server是一套套裝的遊戲伺服器,以往開發線上遊戲都必需自行花費大筆的研 ...
- iPhone X机型适配
1.启动页 启动App,发现App只能居中显示,不能上下充满. 问题产生的原因是:iPhone X是5.8英寸,比5.5英寸的屏幕还要大,没有合适的启动页可以加载,所以只能使用以前5.5英寸的启动页, ...
- C/C++面试题总结(1)
首先说一下,这些东西,有的是必须掌握的,有的是面试时你讲出来就是闪光点.自己把握.把握不好的都搞懂.实在不行背下来. 由于时间关系,总结的比较随意,有的就直接贴链接了,希望理解一下. 第一篇:基础(必 ...
- EXPLAIN 命令
MySQL EXPLAIN 命令详解 MySQL的EXPLAIN命令用于SQL语句的查询执行计划(QEP).这条命令的输出结果能够让我们了解MySQL 优化器是如何执行SQL 语句的.这条命令并没有提 ...
- 【转】Pro Android学习笔记(四六):Dialog(3):对话框弹对话框
目录(?)[-] 帮助提示框的实现 实现再弹框 再谈fragment管理器 提示框的按钮Help,将触发弹出新的帮助提示框. 帮助提示框的实现 帮助提示框的实现很简单,利用重写onCreateView ...
- Uva 213
1. 问题 第一次发现新的存储方式,int code[8][1<<8]; 用于存储二进制的形式 将字符以是十进制的方式存储到数组中 如何消除 \n \r 的影响,进行多行的输入 2. 代码 ...
- VC 绘图,使用双缓冲技术实现
VC 绘图,使用双缓冲技术实现 - Cloud-Datacenter-Renewable Energy-Big Data-Model - 博客频道 - CSDN.NET VC 绘图,使用双缓冲技术实现 ...
- Ubuntu Linux 使用桂电校园网 上网
2016年9月1日 星期四 桂电校园网今天升级新的出校器,旧的出校器已经不能使用,所以本篇博客已经过期,下面的方法已经不能让Ubuntu使用桂电校园网上外网了.详细的原因,请到这个网站查看:校园网计费 ...
- 13、Actor
1.介绍 Scala的Actor类似于Java中的多线程编程.但是不同的是,Scala的Actor提供的模型与多线程有所不同. Scala的Actor尽可能地避免锁和共享状态,从而避免多线程并发时出现 ...
- c#中Marshal.Copy()方法的使用
c#中Marshal.Copy方法的使用 Marshal.copy()方法用来在托管对象(数组)和非托管对象(IntPtr)之间进行内容的复制 函数有很多重载,如下所示: Copy(array< ...