同样的代码在java和c++中结果不同

 #include <iostream>
 using namespace std;
 /* run this program using the console pauser or add your own getch, system("pause") or input loop */
 class A {
     public:
         void m() {
             n();
         }

     public:
         virtual void n() {
             cout<<"调用了父类的n函数";
         }

 };

 class B:public A {

     public:
         void m() {
             A::m();
         }

     public:
         void n() {
             cout<<"调用了子类的n函数";
         }

 };
 int main(int argc, char** argv) {
     B b;
     b.m();
     return ;
 }

class A
{
public void m()
{
	n();
}
public void n()
{
System.out.println("调用了父类的n函数");
}
}

class B extends A
{

public void m()
{
	super.m();
}

public void n()
{
System.out.println("调用了子类的n函数");
}
}

public class main {
	public static void main(String[] args) {
		// TODO Auto-generated method stub
    B b=new B();
    b.m();
	}
}

c++输出父类，java输出子类。　　

原因java默认多态，动态绑定。c++需要加virtual,加上后均为子类