ArrayList 进阶方法之ListIterator

同样看的都是jdk1.8 中 ArrayList中的源码,整理测试一下而已
ListIterator(int index)方法，返回指定下标(包含该下标)后的值，此时index位置的元素就是新列表迭代器的第一个值。是不是感觉有点像substring(intindex)?
注：ArrayList类同时还提供了 listIterator() 方法，此方法与listIterator(int index)的差异是index=0,
此方法可以将ArrayList转换成ListIterator.
下面是源码及测试代码

源码：

     /**
      * Returns a list iterator over the elements in this list (in proper
      * sequence), starting at the specified position in the list.
      * The specified index indicates the first element that would be
      * returned by an initial call to {@link ListIterator#next next}.
      * An initial call to {@link ListIterator#previous previous} would
      * return the element with the specified index minus one.
      *
      * <p>The returned list iterator is <a href="#fail-fast"><i>fail-fast</i></a>.
      *
      * @throws IndexOutOfBoundsException {@inheritDoc}
      */
     public ListIterator<E> listIterator(int index) {
         if (index < 0 || index > size)
             throw new IndexOutOfBoundsException("Index: "+index);
         return new ListItr(index);
     }

测试代码：

 import java.util.ListIterator;

 public class listIteratorTest {
     public static void main(String[] args) {
         ArrayList<String> list = new ArrayList<String>();
         list.add("a");
         list.add("b");
         list.add("c");
         list.add("d");
         list.add("e");
         ListIterator<String> a = list.listIterator(2);
         while (a.hasNext()) {
             System.out.println(a.next());
         }

     }
 }

 运行结果：
 c
 d
 e