hdu 2199 Can you solve this equation? 二分

Can you solve this equation?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6763    Accepted Submission(s): 3154

Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

 

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

 

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

 

Sample Input

2

100 -4

 

Sample Output

1.6152

No solution!

 

Author

Redow

 

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 /*
 对于精度，我表示囧。
 我以为，保留4位小数，就到1e-5就可以了。

 */

 #include<iostream>
 #include<stdio.h>
 #include<cstring>
 #include<cstdlib>
 #include<math.h>
 using namespace std;

 double fun(double x)
 {
     return *x*x*x*x+*x*x*x+*x*x+*x+;
 }
 void EF(double l,double r,double Y)
 {
     double mid;
     while(r-l>1e-)
     {
         mid=(l+r)/;
         double ans=fun(mid);
         if( ans >Y )
             r=mid-1e-;
         else l=mid+1e-;
     }
     printf("%.4lf\n",(l+r)/);
 }
 int main()
 {
     int T;
     double Y;
     scanf("%d",&T);
     {
         while(T--)
         {
             scanf("%lf",&Y);
             if( fun(0.0)>Y || fun(100.0)<Y)
                 printf("No solution!\n");
             else
                  EF(0.0,100.0,Y);
         }
     }
     return ;
 }