ZCMU训练赛-B(dp/暴力)
B - Break Standard Weight
The balance was the first mass measuring instrument invented. In its traditional form, it consists of a pivoted horizontal lever of equal length arms, called the beam, with a weighing pan, also called scale, suspended from each arm (which is the origin of the originally plural term "scales" for a weighing instrument). The unknown mass is placed in one pan, and standard masses are added to this or the other pan until the beam is as close to equilibrium as possible. The standard weights used with balances are usually labeled in mass units, which are positive integers.
With some standard weights, we can measure several special masses object exactly, whose weight are also positive integers in mass units. For example, with two standard weights 1 and 5, we can measure the object with mass 1, 4, 5 or 6exactly.
In the beginning of this problem, there are 2 standard weights, which masses are x and y. You have to choose a standard weight to break it into 2 parts, whose weights are also positive integers in mass units. We assume that there is no mass lost. For example, the origin standard weights are 4 and 9, if you break the second one into 4and 5, you could measure 7 special masses, which are 1, 3, 4, 5, 8, 9, 13. While if you break the first one into 1 and 3, you could measure 13special masses, which are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13! Your task is to find out the maximum number of possible special masses.
Input
There are multiple test cases. The first line of input is an integer T < 500 indicating the number of test cases. Each test case contains 2 integersx and y. 2 ≤ x, y ≤ 100
Output
For each test case, output the maximum number of possible special masses.
Sample Input
2
4 9
10 10
Sample Output
13
9
#include<iostream>
#include<string.h>
#include<stdio.h>
#include<ctype.h>
#include<algorithm>
#include<stack>
#include<queue>
#include<set>
#include<map>
#include<math.h>
#include<vector>
#include<deque>
#include<list>
#define INF 0x7fffffff
#define inf 0x3f3f3f3f
using namespace std;
int f(int x,int y,int z)
{
int r[];
set<int> s;
r[]=x;
r[]=y;
r[]=z;
r[]=x+y ;
r[]=x+z;
r[]=y+z;
r[]=x-y;
r[]=y-z;
r[]=x-z;
r[]=y-x;
r[]=z-x;
r[]=z-y;
r[]=x-y-z;
r[]=x-y+z;
r[]=y-x-z;
r[]=y-x+z;
r[]=y-z+x;
r[]=z-x+y;
r[]=z-x-y;
r[]=x+y+z;
for(int i=;i<;i++)
{
if(r[i]>)
s.insert(r[i]);
}
return s.size();
} int main()
{
int t,a,b;
int maxn, sum;
scanf("%d",&t);
while(t--)
{
maxn=;
scanf("%d%d",&a,&b);
for(int i=; i<a/+; i++)
{
sum=f(i,a-i,b);
maxn=max(maxn,sum);
}
for(int i=; i<b/+; i++)
{
sum=f(a,i,b-i);
maxn=max(maxn,sum);
}
printf("%d\n",maxn);
}
return ;
}
ZCMU训练赛-B(dp/暴力)的更多相关文章
- ZCMU训练赛-J(循环节+字符串处理)
J - Java Beans There are N little kids sitting in a circle, each of them are carrying some java bean ...
- ZCMU训练赛-H(模拟)
H - Hard to Play MightyHorse is playing a music game called osu!. After playing for several months ...
- ZCMU训练赛-A(模拟)
A - Applications https://vjudge.net/contest/174208#overview Recently, the ACM/ICPC team of Marjar Un ...
- HDU6578 2019HDU多校训练赛第一场 1001 (dp)
HDU6578 2019HDU多校训练赛第一场 1001 (dp) 传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6578 题意: 你有n个空需要去填,有 ...
- 10.0.0.55_12-16训练赛部分writeup
0x1 - MISC MISC100 一张帅行的照片 目测是图片隐写,但是binwalk并没有出来,应该是对文件头进行了修改 010editor查看一下,发现在jpg文件尾之后还有大量的数据 而且在灰 ...
- 7.30 正睿暑期集训营 A班训练赛
目录 2018.7.30 正睿暑期集训营 A班训练赛 T1 A.蔡老板分果子(Hash) T2 B.蔡老板送外卖(并查集 最小生成树) T3 C.蔡老板学数学(DP NTT) 考试代码 T2 T3 2 ...
- HDU6579 2019HDU多校训练赛第一场1002 (线性基)
HDU6579 2019HDU多校训练赛第一场1002 (线性基) 传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6579 题意: 两种操作 1.在序列末 ...
- Contest1592 - 2018-2019赛季多校联合新生训练赛第二场(部分题解)
Contest1592 - 2018-2019赛季多校联合新生训练赛第二场 D 10248 修建高楼(模拟优化) H 10252 组装玩具(贪心+二分) D 传送门 题干 题目描述 C 市有一条东西走 ...
- Contest1585 - 2018-2019赛季多校联合新生训练赛第一场(部分题解)
Contest1585 - 2018-2019赛季多校联合新生训练赛第一场 C 10187 查找特定的合数 D 10188 传话游戏 H 10192 扫雷游戏 C 传送门 题干: 题目描述 自然数中除 ...
随机推荐
- Spring事务只对运行时异常回滚
我们在使用Spring时候一般都知道事务在遇到异常的时候会回滚,岂不知Spring的事务默认只有在发生运行时异常即:RunTimeException时才会发生事务,如果一个方法抛出Exception或 ...
- 线程 ManualResetEvent 类
Reset(): 当一个线程开始一个活动(此活动必须完成后,其他线程才能开始)时, 它调用 Reset 以将 ManualResetEvent 置于非终止状态.此线程可被视为控制 ManualRese ...
- 在Debian9安装node和npm
这学期又快结束了,坐在每天面对的电脑面,本着整理资料.更换心情的目的,我重装了一下自己的debian.下面就将自己安装node的过程进行记录与分享. node的官网:https://nodejs.or ...
- 转:Linux 目录结构和常用命令
转自:http://www.cnblogs.com/JCSU/articles/2770249.html仅为学习参考之用 一.Linux目录结构 你想知道为什么某些程序位于/bin下,或者/sbin, ...
- 51Nod-1586-约数和
#include <cstdio> using namespace std; typedef long long ll; ; int n, q; int cnt[MAXN]; ll a[M ...
- Spring - IoC(7): 延迟实例化
默认情况下,Spring IoC 容器启动后,在初始化过程中,会以单例模式创建并配置所有使用 singleton 定义的 Bean 的实例.通常情况下,提前实例化 Bean 是可取的,因为这样在配置中 ...
- Web.xml过滤器配置及执行顺序概念
第一个过滤器 @Overridepublic void doFilter(ServletRequest request, ServletResponse response,FilterChain ch ...
- 【Foreign】猜测 [费用流]
猜测 Time Limit: 10 Sec Memory Limit: 256 MB Description Input Output Sample Input 3 1 1 1 2 2 1 Samp ...
- 【Foreign】置换 [数论][置换]
置换 Time Limit: 10 Sec Memory Limit: 256 MB Description Input Output Sample Input 4 2 1 4 3 Sample O ...
- 金中欢乐赛 A题
题目传送门 这道题就贪心.... 正的一坨和负的一坨间隔 #include<cstdio> #include<cstring> #include<algorithm> ...