It was proposed by Christian Goldbach that every odd composite number can be written as the sum of a prime and twice a square.

9 = 7 + 212
15 = 7 + 222
21 = 3 + 232
25 = 7 + 232
27 = 19 + 222
33 = 31 + 212

It turns out that the conjecture was false.

What is the smallest odd composite that cannot be written as the sum of a prime and twice a square?

题目大意:

Christian Goldbach 提出每个奇合数都可以写作一个质数与一个平方数的二倍之和:

9 = 7 + 212
15 = 7 + 222
21 = 3 + 232
25 = 7 + 232
27 = 19 + 222
33 = 31 + 212

但是这个推测是错误的。

最小的不能写作一个质数与一个平方数的二倍之和的奇合数是多少?

//(Problem 46)Goldbach's other conjecture
// Completed on Fri, 26 Jul 2013, 16:58
// Language: C11
//
// 版权所有(C)acutus (mail: acutus@126.com)
// 博客地址:http://www.cnblogs.com/acutus/
#include<stdio.h>
#include<math.h>
#include<string.h>
#include<ctype.h>
#include<stdlib.h>
#include<stdbool.h> bool issquare(int n) //判断一个自然数是否为一个平方数
{
if(ceil(sqrt(n))*ceil(sqrt(n))==n) return true;
else return false;
} bool isprim(int n) //素数判断
{
for(int i=; i*i<=n; i++)
{
if(n%i==) return false;
}
return true;
} bool judge(long long n)
{
int i=;
long long t;
while((t=(n-*(i*i)))>)
{
if(isprim(t)) return true;
i++;
}
return false;
} int main()
{
for(long long i=; i<; i=i+)
{
if(!isprim(i) && !judge(i))
{
printf("%lld\n",i);
break;
}
}
return ;
}
Answer:
5777

(Problem 46)Goldbach's other conjecture的更多相关文章

  1. (Problem 73)Counting fractions in a range

    Consider the fraction, n/d, where n and d are positive integers. If nd and HCF(n,d)=1, it is called ...

  2. (Problem 42)Coded triangle numbers

    The nth term of the sequence of triangle numbers is given by, tn = ½n(n+1); so the first ten triangl ...

  3. (Problem 41)Pandigital prime

    We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly o ...

  4. (Problem 70)Totient permutation

    Euler's Totient function, φ(n) [sometimes called the phi function], is used to determine the number ...

  5. (Problem 74)Digit factorial chains

    The number 145 is well known for the property that the sum of the factorial of its digits is equal t ...

  6. (Problem 72)Counting fractions

    Consider the fraction, n/d, where n and d are positive integers. If nd and HCF(n,d)=1, it is called ...

  7. (Problem 53)Combinatoric selections

    There are exactly ten ways of selecting three from five, 12345: 123, 124, 125, 134, 135, 145, 234, 2 ...

  8. (Problem 49)Prime permutations

    The arithmetic sequence, 1487, 4817, 8147, in which each of the terms increases by 3330, is unusual ...

  9. (Problem 47)Distinct primes factors

    The first two consecutive numbers to have two distinct prime factors are: 14 = 2  7 15 = 3  5 The fi ...

随机推荐

  1. Python之lxml

    作者:Shane 出处:http://bluescorpio.cnblogs.com lxml takes all the pain out of XML. Stephan Richter lxml是 ...

  2. spm3 基本

    spm3 命令 spm init //初始化一个spm模块,会生成基本配置以及测试文件等(下图). //注 初始化以后一般需要 鲜执行一下 spm install 安装默认依赖模块 index.js就 ...

  3. samba服务器的安装及配置

    安装前首先查看服务器是否已经安装samba服务器 [root@bogon home]# rpm -qa|grep samba system-config-samba-docs-1.0.9-1.el6. ...

  4. 手机root初体验

    看到别人写的一些自己想知道的东西,顿时感到很有兴趣也很强大,固然做一个牛人有很多小粉丝是无比崇高的,可去往牛人的路上也不能少了自己~加油! 一 我来解释一下什么是ROOT以及原理 是不是要ROOT,是 ...

  5. SQLite 终端相关命令

    SQLite ALL Last login: Fri Dec  5 09:52:08 on ttys002 BeSilent:~ qianfeng$ sqlite3 data.db SQLite ve ...

  6. Oracle包的概念

    转自:http://www.cnblogs.com/lovemoon714/archive/2012/02/29/2373695.html 1.为什么要使用包?       答: 在一个大型项目中,可 ...

  7. Hibernate知识总结(一)——Hibernate原理概述

    一.Hibernate是什么: 它是一个持久化框架,它对JDBC进行了轻量级的封装,简化对数据库的操作,提高开发效率.和另一个持久化框架MyBatis一样,他们操作数据库都是通过一个session对象 ...

  8. 同步队列-Queue模块解析

    Queue模块解决了生产者.消费者问题,在多线程编程中进行线程通信的时候尤其有用,Queue类封装了加锁解锁的过程.         在Queue模块中有三种不同的队列类,区别是不同队列取出数据的顺序 ...

  9. jQuery实现导航监听事件

    导航html如下 <div class="main_nav"> <a class="nav_01 active_01" href=" ...

  10. html5 canvas 运行起来绝对让你震撼!

    从一个大神那看到的,拷贝过来跟大家分享下! html <canvas></canvas> *{margin:0;padding:0;}body{background:#222; ...