Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

解题思路:

修改上题代码即可,JAVA实现如下:

public ListNode deleteDuplicates(ListNode head) {
if (head == null || head.next == null)
return head;
ListNode temp = head.next;
if (temp.val == head.val) {
while (temp.val == head.val) {
temp = temp.next;
if (temp == null) {
head.next = null;
return head;
}
}
head.next = temp;
}
temp = head.next;
ListNode last = head;
while (temp != null && temp.next != null) {
if (temp.val != temp.next.val) {
last.next = temp;
temp = temp.next;
last = last.next;
continue;
}
last.next = temp;
last=last.next;
while (temp.val == last.val) {
temp = temp.next;
if (temp == null) {
last.next = null;
return head;
}
}
}
last.next = temp;
return head;
}

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