Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.

class Solution {
public:
    int hammingWeight(uint32_t n) {
    int i,res=0;
    for(i=0;i<32;i++)
    {
        if(n%2==1)
            {res++;}
            //return n;
          n = n>>1;//这里要进行赋值,不然不会改变n的值
        //return n;
   
    }
    return res;
    }
};

Number of 1 BitsWrite a function that takes an unsigned integer and returns the number of ’1' bits i的更多相关文章

  1. pug.compile() will compile the Pug source code into a JavaScript function that takes a data object (called “locals”) as an argument.

    Getting Started – Pug https://pugjs.org/api/getting-started.html GitHub - Tencent/wepy: 小程序组件化开发框架 h ...

  2. vue引入fastclick设置输入框type="number"报错Failed to execute 'setSelectionRange' on 'HTMLInputElement': The input element's type ('number') does not support selection.的解决办法

    将输入框type设为text,通过正则验证输入的值

  3. [LeetCode] Number of 1 Bits 位1的个数

    Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also know ...

  4. 【leetcode】Number of 1 Bits

    题目描述: Write a function that takes an unsigned integer and returns the number of '1' bits it has (als ...

  5. Number of 1 Bits(Difficulty: Easy)

    题目: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also ...

  6. LeetCode 191 Number of 1 Bits

    Problem: Write a function that takes an unsigned integer and returns the number of '1' bits it has ( ...

  7. leetCode191/201/202/136 -Number of 1 Bits/Bitwise AND of Numbers Range/Happy Number/Single Number

    一:Number of 1 Bits 题目: Write a function that takes an unsigned integer and returns the number of '1' ...

  8. Java for LeetCode 191 Number of 1 Bits

    Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also know ...

  9. (easy)LeetCode 191.Number of 1 Bits

    Number of 1 Bits Write a function that takes an unsigned integer and returns the number of ’1' bits ...

随机推荐

  1. Nuget:Newtonsoft.Json

    ylbtech-Nuget:Newtonsoft.Json 1.返回顶部   2.返回顶部 1,Serialize JSON Product product = new Product(); prod ...

  2. UItextFied 的属性

    网络学习笔记 在iPhone应用中通过UITextField填写信息时,经常出现出现自动更正输入信息.首字母大写等情况 尤其是在填写用户名时,这种本想提供便捷的功能反而让人感到特别麻烦 今天查了相关书 ...

  3. sql之外键变种

    多对一 : 只需设个外键 外键变种之一对一:普通外键关联的表是一对多关系,如果外键上再加上唯一索引,表就会变成一对一关系. 外键变种之多对多:

  4. yzm10铺瓷砖 yzm10原创系列

    yzm10铺瓷砖 一天yzm10接到任务,要求用2×1大小的瓷砖,来铺2×4的地面,地面需要恰好被铺满.这对yzm10来说太容易了,于是他马上设计出了5种不同的铺法(旋转情况算不同种,如图示2.4). ...

  5. 《剑指offer》面试题16—反转链表

    Node* p1  p2  p3 思路:开始时,p1为NULL,p2=phead,p3=p2—>next.使p2—>next = p1,然后使p1=p2,p2=p3.如果只有1个结点则此时 ...

  6. memcached 命令详解

    memcached::get(); //查找key的值: 例:$mem->get($key): memcached::add() ; //添加,当key存在时,false,当key不存在则执行 ...

  7. 2014-5-24 NOIP模拟赛

    Problem 1 护花(flower.cpp/c/pas) [题目描述] 约翰留下他的N(N<=100000)只奶牛上山采木.他离开的时候,她们像往常一样悠闲地在草场里吃草.可是,当他回来的时 ...

  8. uoj#276. 【清华集训2016】汽水(分数规划+点分治)

    传送门 没想到点分治那一层-- 首先不难发现这是个分数规划,先把所有的边长减去\(k\),二分答案,设为\(mid\),就是要求路径平均值\(ans\in[-mid,mid]\) 先来考虑\(ans\ ...

  9. 洛谷P3265 [JLOI2015]装备购买(线性基+高斯消元)

    传送门 不知道线性基是什么东西的可以看看蒟蒻的总结 不难看出题目讲的就是线性基 这种最小化权值的问题一般都是贪心的,就是按价值从低到高考虑每一个是否能选 据说贪心的证明得用拟阵我不会 据说这题是实数意 ...

  10. Luogu P1074靶形数独【搜索/剪枝】By cellur925

    题目传送门 显然是一个搜索.但是开始没有任何的剪枝,暴力从\((1,1)\)点开始搜索,很自然地T了6个点. #include<cstdio> #include<algorithm& ...