L216: Combination Sum III

  Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.

Ensure that numbers within the set are sorted in ascending order.

Example 1:

Input: k = 3, n = 7

Output:

[[1,2,4]]

Example 2:

Input: k = 3, n = 9

Output:

[[1,2,6], [1,3,5], [2,3,4]]

解题思路:递归,注意一些条件的处理,避免不必要的处理

class Solution {
public:
bool combine(int min, int k, int n, vector<int> vec, vector<vector<int>>& result){
if(n<min*k) //更确切的。能够用等差数列公式算出最大值最小值
return false;
if(n>9*k)
return true; if(k==1)
{
vec.push_back(n);
result.push_back(vec);
return true;
} for(int i=min;i<=9;i++)
{
vec.push_back(i);
bool rt = combine(i+1, k-1,n-i, vec, result);
vec.pop_back();
if(!rt)
break;
}
return true;
} vector<vector<int>> combinationSum3(int k, int n) {
vector<vector<int>> result;
vector<int> vec;
combine(1,k,n,vec,result);
return result;
}
};

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