页面跳转时候拼接在url后面的多个 参数获取

   function GetRequest() {
         var url = location.search;
         var theRequest = new Object();
         if (url.indexOf("?") != -1) {
             var str = url.substr(1);
             strs = str.split("&");
             for (var i = 0; i < strs.length; i++) {
                 theRequest[strs[i].split("=")[0]] = decodeURI(strs[i].split("=")[1]);
             }
         }
         console.log(theRequest)
         return theRequest;
     }
     var params={};
     params=GetRequest();
     var processDefinitionName=params['processDefinitionName'];