Code froces 831 A. Unimodal Array
1 second
256 megabytes
standard input
standard output
Array of integers is unimodal, if:
- it is strictly increasing in the beginning;
- after that it is constant;
- after that it is strictly decreasing.
The first block (increasing) and the last block (decreasing) may be absent. It is allowed that both of this blocks are absent.
For example, the following three arrays are unimodal: [5, 7, 11, 11, 2, 1], [4, 4, 2], [7], but the following three are not unimodal: [5, 5, 6, 6, 1], [1, 2, 1, 2], [4, 5, 5, 6].
Write a program that checks if an array is unimodal.
The first line contains integer n (1 ≤ n ≤ 100) — the number of elements in the array.
The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 1 000) — the elements of the array.
Print "YES" if the given array is unimodal. Otherwise, print "NO".
You can output each letter in any case (upper or lower).
6
1 5 5 5 4 2
YES
5
10 20 30 20 10
YES
4
1 2 1 2
NO
7
3 3 3 3 3 3 3
YES
#include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <vector>
#include <cstdlib>
#include <iomanip>
#include <cmath>
#include <ctime>
#include <map>
#include <set>
using namespace std;
#define lowbit(x) (x&(-x))
#define max(x,y) (x>y?x:y)
#define min(x,y) (x<y?x:y)
#define MAX 100000000000000000
#define MOD 1000000007
#define pi acos(-1.0)
#define ei exp(1)
#define PI 3.141592653589793238462
#define INF 0x3f3f3f3f3f
#define mem(a) (memset(a,0,sizeof(a)))
typedef long long ll;
int main()
{
int a[],n,x;
scanf("%d",&n);
for(int i=;i<=n;i++)
{
scanf("%d",&a[i]);
}
int l=,r=n;
while(l<n && a[l]<a[l+]) l++;
while(r> && a[r]<a[r-]) r--;
for(int i=l+;i<=r;i++)
if(a[i]!=a[l]) return puts("NO"),;
puts("YES");
return ;
}
Code froces 831 A. Unimodal Array的更多相关文章
- Codeforces831A Unimodal Array
A. Unimodal Array time limit per test 1 second memory limit per test 256 megabytes input standard in ...
- CodeForces - 831A Unimodal Array 模拟
A. Unimodal Array time limit per test 1 second memory limit per test 256 megabytes input standard in ...
- 【Codeforces Round #424 (Div. 2) A】Unimodal Array
[Link]:http://codeforces.com/contest/831/problem/A [Description] 让你判断一个数列是不是这样一个数列: 一开始是严格上升 然后开始全都是 ...
- E - Unimodal Array CodeForces - 831A
Array of integers is unimodal, if: it is strictly increasing in the beginning; after that it is cons ...
- Codeforces Round #424 (Div. 2, rated, based on VK Cup Finals)
http://codeforces.com/contest/831 A. Unimodal Array time limit per test 1 second memory limit per te ...
- C++ std::array
std::array template < class T, size_t N > class array; Code Example #include <iostream> ...
- Array.prototype.slice.call(document.querySelectorAll('a'), 0)
Array.prototype.slice.call(document.querySelectorAll('a'), 0)的作用就是将一个DOM NodeList 转换成一个数组. slice()方法 ...
- [转]Passing Managed Structures With Strings To Unmanaged Code Part 3
1. Introduction. 1.1 In part 1 of this series of blogs we studied how to pass a managed structure (w ...
- [转]Passing Managed Structures With Strings To Unmanaged Code Part 2
1. Introduction. 1.1 In part 1 of this series of blogs we studied how to pass a managed structure (w ...
随机推荐
- Android开发之Volley网络通信框架
今天用了一下Volley网络通信框架,感觉挺好用的,写个博客记录一下用法.方便以后VC. Volley(Google提供的网络通信库,能使网络通信更快,更简单,更健壮.) 功能模块: 1. JSON, ...
- 线程池系列三:ThreadPoolExecutor讲解
三.一个用队列处理线程池例子 package demo; import java.util.Queue; import java.util.concurrent.ArrayBlockingQueue; ...
- BZOJ1045: [HAOI2008]糖果传递&BZOJ1465: 糖果传递&BZOJ3293: [Cqoi2011]分金币
[传送门:BZOJ1045&BZOJ1465&BZOJ3293] 简要题意: 给出n个数,每个数每次可以-1使得左边或者右边的数+1,代价为1,求出使得这n个数相等的最小代价 题解: ...
- 智课雅思短语---二、exert positive/ negative effects on…
智课雅思短语---二.exert positive/ negative effects on… 一.总结 一句话总结:对…产生有利/不利的影响 1.the advantages far outweig ...
- Redis之创建
redis配置文件信息 public sealed class RedisConfigInfo { /// <summary> /// 可写的Redis链接地址 /// format:ip ...
- canvas和svg小记
一.关于canvas <canvas> 是 HTML5 新增的元素,可用于通过使用JavaScript中的脚本来绘制图形 例如,它可以用于绘制图形,创建动画. <canvas> ...
- CSUOJ 1549 Navigition Problem
1549: Navigition Problem Time Limit: 1 Sec Memory Limit: 256 MBSubmit: 65 Solved: 12 Description N ...
- codevs——T1006 等差数列
http://codevs.cn/problem/1006/ 时间限制: 1 s 空间限制: 128000 KB 题目等级 : 黄金 Gold 题解 查看运行结果 题目描述 Descr ...
- hdu4565---So Easy!(矩阵)
Problem Description A sequence Sn is defined as: Where a, b, n, m are positive integers.┌x┐is the ce ...
- android反编译odex文件
关于android的反编译工具,相信大家并不陌生 如APK-TOOL,dex2jar APK-TOOL 用于反编译出布局文件 下载地址http://code.google.com/p/android- ...